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Trava [24]
3 years ago
5

When two waves are in sync with each other and occupy the same place at the same time, how is the resulting wave determined?

Physics
2 answers:
xz_007 [3.2K]3 years ago
8 0
<h3><u>Answer;</u></h3>

<em>By adding the amplitude of the two waves </em>

<h3><u>Explanation;</u></h3>
  • <em><u>Wave is a transmission of a disturbance from one point to another. </u></em>Transmission of waves involves transport of energy from one point called the source to another.
  • <em><u>A characteristic of wave in which two waves meet each other is called an interference.  </u></em>When interference occurs it may either be constructive or destructive. When two waves are in sync with each other and occupy the same place at the same time is called constructive interference. <em><u>The amplitude of the resulting wave is the sum of the two original waves. For constructive interference the amplitude is normally larger than the original.</u></em>
Ainat [17]3 years ago
3 0
<span>When two waves are in sync with each other and occupy the same place at the same time, a constructive interference occurs. To get the resulting wave, the amplitude of each wave is added to produce a wave the represents the result of the constructive interference.</span>
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Answer:3.46

Explanation:

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no. of moles=329/71

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3 years ago
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A 2.0-kilogram ball rolls down a ramp. if the ball accelerates at a rate of 12 m/s2, the net force causing the acceleration is:
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Answer:

D

Explanation:

f = ma

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2 years ago
A child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a
kirill [66]

Answer:

θ = 13.16 °

Explanation:

Lets take mass of child = m

Initial velocity ,u= 1.1 m/s

Final velocity ,v=3.7 m/s

d= 22.5 m

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The friction force = (m g)/5

Now from work power energy

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work done by all forces = change in kinetic energy

( m g sinθ - (m g)/5 ) d = 1/2 m v² - 1/2 m u²

(2  g sinθ - ( 2 g)/5 ) d = v² -  u²

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5 0
3 years ago
A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 1.10 m. If her pisto
lapo4ka [179]

Answer:

The diameter of the piston of the players equals 55.136 cm.

Explanation:

from the principle of transmission of pressure in a hydraulic lift  we have

\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{1}}

Since the force in the question is the weight of the individuals thus upon putting the values in the above equation we get

\frac{57.0\times 9.81}{\frac{\pi \times (19.0)^{2}}{4}}=\frac{4\times 120\times 9.81}{\frac{\pi \times D_{2}^{2}}{4}}

Solving for D_{2} we get

D_{2}^{2}=\frac{4\times 120}{57}\times 19^{2}\\\\\therefore D_{2}=\sqrt{\frac{4\times 120}{57}}\times 19\\\\D_{2}=55.136cm

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