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3 years ago

A student pushes a box with a total mass of 50 kg. What is the net force on the box if it accelerates 1.5 m/s

Physics

2 answers:

Ronch [10]3 years ago

4 0

Answer:

Net force acting on the box is 75 N.

Explanation:

It is given that,

Mass of the box, m = 50 kg

Acceleration of the box, $a=1.5\ m/s^2$

Let F is the net force acting on the box. It can be calculated using the Newton's second law of motion. According to this law the force acting on an object is equal to the product of mass and acceleration with which it is moving. Mathematically, it is given by :

$F=m\times a$

$F=50\ kg\times 1.5\ m/s^2$

F = 75 N

So, the net force acting on the box is 75 N. Hence, this is the required solution.

Harrizon [31]3 years ago

3 0

We now that follow newton rules f=ma so net force equal to mass*acceleration=>f=50*1.5=75 N

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2 years ago

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NISA [10]

Explanation:

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(A) Magnetic field of a current loop is given by :

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3 years ago

A 41.0 g marble moving at 2.30 m/s strikes a 25.0 g marble at rest. What is the speed of each marble immediately after the colli

Gre4nikov [31]

Answer:

speed of each marble after collision will be 1.728 m/sec

Explanation:

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Its collides with other marble of mass 25 gram

So mass of other marble $m_2=25gram=0.025kg$

Second marble is at so $v_2=0m/sec$

We have to find the velocity of second marble

From momentum conservation we know that

$m_1v_1+m_2v_2=(m_!+m_2)v$ , here v is common velocity of both marble after collision

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3 years ago

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klemol [59]

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Explanation:

Let's begin by explaining that Coulomb's Law establishes the following:

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