Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
I hope this helps you
2 (x+x+x+x+x+24+24)=120
4x+48=60
x=3
Area =2x.24
Area =2.3.24
Area =144
Anna has 100 quarters and jazmin has 100 dimes 100 dimes are equal to 10.00 and 100 quarters are equal to 25.00 Anna has more
Answer:
what is the question you are trying to answer? leave a comment below and I will try to answer it .
Step-by-step explanation:
First, do what's in the paranthesis:
(4*4-12)
Multiplication first:
16-12
Then subtract:
4
We get:
5-1+2*4*8
Multiply:
2*4
8
Multiply, again:
8*8
64
We get:
5-1+64
Subtract:
5-1
4
Add:
4+64
Answer: 68
