Answer:
20,7,13. are the most correct for a triangular shape
• Expand (2a + b)²:
(2a + b)²
= (2a + b) · (2a + b)
Multiply out the brackets by applying the distributive property of multiplication:
= (2a + b) · 2a + (2a + b) · b
= 2a · 2a + b · 2a + 2a · b + b · b
= 2²a² + 2ab + 2ab + b²
Now, group like terms together, and you get
= 2²a² + 4ab + b²
= 4a² + 4ab + b² <——— expanded form (this is the answer).
I hope this helps. =)
Tags: <em>special product square of a sum algebra</em>
A1 represents the first term
d represents the common difference.....and since the common difference is 3, u have to add 3 to each term to find the next term....because with an arithmetic sequence u add to find the next term, whereas, in a geometric sequence u multiply to find the next term
5...first term
5 + 3 = 8...2nd term
8 + 3 = 11...3rd term
11 + 3 = 14...4th term
ur answer is B
Answer:
Step-by-step explanation:
c i watch the show
Answer:
3
Step-by-step explanation:
