A chemist has three different acid solutions. The first acid solution contains

1 answer:

5 0

Let t, f, and s be the amount of 25%, 40%, and 60% solutions used.

We are told s=3f. The general equation is:

100(0.25t+0.4f+0.6s)/(t+s+f)=45, and using s=3f we have:

(0.25t+0.4f+1.8f)/(t+4f)=0.45

(0.25t+2.2f)/(t+4f)=0.45

0.25t+2.2f=0.45t+1.8f

0.25t+0.4f=0.45t

0.4f=0.2t

t=2f, remembering that s=3f, will allow us to solve for f

t+s+f=60, using t and s from above

2f+3f+f=60

6f=60

f=10 L then

s=3f=30 L and t=2f=20L

So 20L of 25%, 10L of 40%, and 30L of 60% acid solutions need to be mixed to make 60L of 45% acid solution.

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Listed below are the amounts (dollars) it costs for marriage proposal packages at different baseball stadiums. Find the range,

yulyashka [42]

Answer:

Range = 2460 dollars, Variance = 516414.6 $dollars^2$ , Standard deviation = 718.6199 dollars . There are two outliers and they are likely to have much of an effect on the measures of variation.

Step-by-step explanation:

The smallest value in the sample data is min = 50 dollars and the largest value is max = 2500 dollars, therefore, the range is Range = max - min = 2500 - 40 = 2460 dollars. On the other hand, the formula to compute the sample variance is $S^2 = \frac{1}{n-1}\sum_{i=1}^{n} (x_{i}-\bar{x})^2$ where $\bar{x}$ is the sample mean, n is the sample size and the $x_{i}$ are the sample values. In this case the sample variance is $s^2$ = 516414.6 $dollars^2$ , the sample standard deviation is defined as the squared root of the sample variance, so, the sample standard deviation is s = 718.6199 dollars. There are two outliers because 1750 dollars and 2500 dollars are very different compared to the other values, these two numbers are very large and they are likely to have much of an effect on the measures of variation because these measures are sensible to outliers, they are no robust measures.