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Irina-Kira [14]
3 years ago
11

Although not usually soluble in plain water, an amphoteric oxide or hydroxide is: 1. soluble in neutral solutions. 2. soluble in

acidic solutions and insoluble in basic solutions. 3. soluble in basic solutions and insoluble in acidic solutions. 4. soluble in both acidic and basic solutions.
Chemistry
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

The correct option is: 4. soluble in both acidic and basic solutions

Explanation:

Oxide is a chemical compound formed by an element with oxygen. In such compounds, the oxygen is generally present in the -2 oxidation state.

Whereas, hydroxide is a chemical compound formed by an element with hydroxyl group (-OH).

<em>Oxides and hydroxides of some elements are </em><em>amphoteric</em><em> in nature.</em> <u><em>Such compounds can behave as an acid in basic medium and behave as a base in acidic medium.</em></u>

<u>Therefore, amphoteric oxides and hydroxides are soluble in both acidic and basic solutions.</u>

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What volume of a 6.0m hcl solution is required to make 250.0 milliters of 1.5 m hcl
Georgia [21]

Answer : The volume for 6.0m HCl solution required = 62.5 ml

Solution : Given,

Initial concentration of HCl solution = 6.0m

Final concentration of HCl solution = 1.5m

Final volume of HCl solution = 250 ml

Initial volume of HCl solution = ?

Formula used for dilution is,

M_1V_1=M_2V_2

where,

M_1 = initial concentration

M_2 = final concentration

V_1 = initial volume

V_2 = final volume

Now put all the given values in above formula, we get the initial volume of HCl solution.

6.0m\times V_1=1.5m\times 250ml

V_1 = 62.5 ml

Therefore, the volume for 6.0m HCl solution required = 62.5 ml


8 0
3 years ago
How many moles of Ammonium Sulfate can be made from 30.0mol of NH3? 2NH3 + H2SO4 --&gt; (NH4)2SO4
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Answer: 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

Explanation:

The balanced chemical reaction is :

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4

According to stoichiometry :

2 moles of NH_3 give = 1 mole of (NH_4)_2SO_4

Thus 30.0 moles of NH_3 will give =\frac{1}{2}\times 30.0=15.0moles  of (NH_4)_2SO_4

Thus 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

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3 years ago
Initial alcohol is converted to compound A. Compound A undergoes three different transformations. Name compound A and each the f
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Explanation:

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    3. CH_3COOH + NaHCO_3 → CH_3COONa +CO_2 +H_2O

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2 years ago
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Answer:

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