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andrezito [222]
3 years ago
9

The half-life of tritium, or hydrogen-3, is 12.32 years. After about 37 years, how much of a sample of tritium will remain uncha

nged? A)1/8   B)1/4  C)1/3  D)1/2
Chemistry
2 answers:
Kipish [7]3 years ago
8 0
I think that the answer is 1/8 Hope this helps!!!! :D
Blizzard [7]3 years ago
7 0

The correct option is A) 1/8


half-life of tritium, or hydrogen-3, is 12.32 years.      

After about 37 years,

= 37/12.32

= 3

means 3 half lives.


sample of tritium that will remain unchanged will be:

= 1/2^no.of half lives

= 1/2³

= 1/2 x 1/2 x 1/2 = 1/8

<u> 1/8 remains back</u>





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What are the differences between amorphous and crystalline solids? Give an example of each.
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How many molecules of carbon dioxide are dissolved in 0.550 L of water at 25 °C if the pressure of CO2 above the water is 0.250
Grace [21]

<u>Answer:</u> The number of molecules of carbon dioxide gas are 2.815\times 10^{21}

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.034mol/L.atm

C_{CO_2} = molar solubility of carbon dioxide gas

p_{CO_2} = pressure of carbon dioxide gas = 0.250 atm

Putting values in above equation, we get:

C_{CO_2}=0.034mol/L.atm\times 0.250atm\\\\C_{CO_2}=8.5\times 10^{-3}M

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of carbon dioxide = 8.5\times 10^{-5}M

Volume of solution = 0.550 L

Putting values in above equation, we get:

8.5\times 10^{-3}M=\frac{\text{Moles of }CO_2}{0.550L}\\\\\text{Moles of }CO_2=(8.5\times 10^{-3}mol/L\times 0.550L)=4.675\times 10^{-3}mol

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of molecules

So, 4.675\times 10^{-3} moles of carbon dioxide will contain = (6.022\times 10^{23}\times 4.675\times 10^{-3})=2.815\times 10^{21} number of molecules

Hence, the number of molecules of carbon dioxide gas are 2.815\times 10^{21}

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3 years ago
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