Answer: Calcium sulfide is a chemical compound having formula CaS. While Calcium sulfide is inorganic compound g fomlaCaSO4.
Explanation:
calcium sulfide is use in preparation of hydrogen sulfide, luminous pain and as a depilatory in cosmetics while calcium sulfate is used as desiccant. calcium sulfides is white material crystallizes in cubes like rock salt while calcium sulfate has three different crystalized forms known as hemihydrate (CaSO4⋅12H2O) , anhydrate (CaSO4) and as gypsum (CaSO4⋅2H2O). hope this explanation will be helpful for you
When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.
<h3>What is Limiting reagent ?</h3>
Limiting reagents are the substances that are completely consumed first in a chemical reaction.
Given ;
- Amopunt of Zn : 1 mole
- Amount of O₂ : 2 mole
Given equation ;
2Zn + O₂ --> 2ZnO
As according to given chemical equation,
2 moles Zn of reacts with 1 mole of O₂ to produce 2 moles of ZnO.
Therefore,
1 mole of Zn will require 0.5 mole of O₂.
But,
the given amount of O₂ is 2 mole which is excess
Hence,
Zn here will act as the Limiting reagent, According to which the amount of product formed will be decided.
Therefore,
If 2 mole Zn produces : 2 moles of ZnO (According to given balanced equation)
Thus,
1 mole of Zn will produce = 2/2 x 1
= 1 mole of ZnO
Hence, When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.
Learn more about Limiting reagent here ;
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Will be destroyed unless helped.
The Answer will be
A, B, and D
Not entirely sure though, comment if I'm wrong about this or delete this so no one else gets it wrong if it is
Answer:
15.06 L
Explanation:
Using the ideal gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information provided in this question,
P = 3.50 atm
n = 1.9 moles
V = ?
T = 65°C = 65 + 273 = 338K
Using PV = nRT
V = nRT/P
V = (1.9 × 0.0821 × 338) ÷ (3.5)
V = 52.725 ÷ 3.5
V = 15.06 L
