2 years ago

An ionic compound contains

Chemistry

1 answer:

hodyreva [135]2 years ago

7 0

Answer:

an ionic compound contains ions

Explanation:

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IgorC [24]

Answer:

Electrons

Explanation:

Atoms can combine together and share electrons between them. Atoms that share electrons are linked to each other in a form, called a molecule that is in a lower energy state than either of the separate atoms alone.

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2 years ago

How will the concentration of H+ and OH− ions change when a substance with a pH 3.2 is added to water? Both H+ and OH− will incr

Lunna [17]

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Under certain conditions, the equilibrium constant of the reaction below is Kc=1.7×10−3. If the reaction begins with a concentra

svetoff [14.1K]

Answer:

[Cl2] equilibrium = 0.0089 M

Explanation:

Given:

[SbCl5] = 0 M

[SbCl3] = [Cl2] = 0.0546 M

Kc = 1.7*10^-3

To determine:

The equilibrium concentration of Cl2

Calculation:

Set-up an ICE table for the given reaction:

$SbCl5(g)\rightleftharpoons SbCl3(g)+Cl2(g)$

I 0 0.0546 0.0546

C +x -x -x

E x (0.0546-x) (0.0546-x)

$Kc = \frac{[SbCl3][Cl2]}{[SbCl5]}\\\\1.7*10^{-3} =\frac{(0.0546-x)^{2} }{x} \\\\x = 0.0457 M$

The equilibrium concentration of Cl2 is:

= 0.0546-x = 0.0546-0.0457 = 0.0089 M

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How many moles of solute are in 53.1 mL of 12.5M HCI?

Deffense [45]

Molarity = moles of solute/volume of solution in liters.

From this relation, we can figure out the number of moles of solute by multiplying the molarity of the solution by the volume in liters.

We have 53.1 mL, or 0.0531 L, of a 12.5 M, or 12.5 mol/L, solution. Multiplying 12.5 mol/L by 0.0531 L, we obtain 0.664 moles. So, in this volume of solution, there are 0.664 moles of solute (HCl).

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1 year ago