Answer:
GLUCOSE aka SUGAR
Explanation:
<u>glucose</u><u> </u><u>-</u><u> </u><u>A</u><u> </u><u>simple</u><u> </u><u>sugar</u><u> </u><u>which</u><u> </u><u>is</u><u> </u><u>an</u><u> </u><u>important</u><u> </u><u>energy</u><u> </u><u>source</u><u> </u><u>in</u><u> </u><u>livong</u><u> </u><u>organisms</u><u> </u><u>and</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>component</u><u> </u><u>of</u><u> </u><u>many</u><u> </u><u>carbohydrates</u><u>.</u>
Glucose, found in the food animals eat, is broken down during the process of cellular respiration into an energy source called ATP.
Hope this helped !
Answer:
27.60 g urea
Explanation:
The <em>freezing-point depression</em> is expressed by the formula:
In this case,
- ΔT = 5.6 - (-0.9) = 6.5 °C
m is the molality of the urea solution in X (mol urea/kg of X)
First we<u> calculate the molality</u>:
- 6.5 °C = 7.78 °C kg·mol⁻¹ * m
Now we<u> calculate the moles of ure</u>a that were dissolved:
550 g X ⇒ 550 / 1000 = 0.550 kg X
- 0.84 m = mol Urea / 0.550 kg X
Finally we <u>calculate the mass of urea</u>, using its molecular weight:
- 0.46 mol * 60.06 g/mol = 27.60 g urea
Yes, a compound is a type of matter.
Answer: B
Your answer would be ecosystem because ecosystem is all the living things in an area interacting with all of the abiotic parts of the environment.