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Vika [28.1K]
3 years ago
8

Calculate the percentage by mass of water in magnesium sulfate heptahydrate, MgSO4•7H2O

Chemistry
2 answers:
Aleksandr-060686 [28]3 years ago
7 0

Answer:from reffered dfn of %by mass

%by M=mass of component particular/total mass

But mass directly proportional to Molar mass

% by M=molar mass of H2O cpn/total M

%by M=7((1×2)+16)/(7((1×2)+16)+(24+(16×4)+32))

=0.573

masha68 [24]3 years ago
3 0

Answer:

The percentage  by mass of water in magnesium sulfate heptahydrate is 51.2 %

Explanation:

<u>Step 1:</u> Data given

Molar mass of MgSO4*7H2O = 246.5 g/mol

Molar mass of H2O = 18.02 g/mol

Molar massof MgSO4 = 120.37 g/mol

<u>Step 2:</u> Calculate % water in magnesium sulfate heptahydrate

Since we have 7 molecules of water in the heptahydrate, we will divide the molar mass of 7 molecules water by the molar mass of the heptahydrate.

m%(H2O) = (7*18.02)/ 246.5

m%(H2O) = (126.14 /246.5)*100%

m%(H2O) = 51.2 %

To controle this we will calculate the mass % of MgSO4

m%(MgSO4) = (120.37/ 246.50)*100%

m%(MgSO4) = 48.8%

51.2 + 48.8 = 100%

The percentage  by mass of water in magnesium sulfate heptahydrate is 51.2 %

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The isotope of an atom containing 31 protons and 39 neutrons suddenly has two neutrons added to it.
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Answer:

Gallium-72

Explanation:

The elements are identified by the number of protons of the atom, which is its atomic number.

In this case the number of protons 39 (atomic number 39) permit you to identify the element as gallium.

Now, to identify the isotope you tell the name of the element and add the mass number.

The mass number is the sum of the protons and the neutrons

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3 years ago
If 3.53 g of CuNO, is dissolved in water to make a 0.330 M solution, what is the volume of the solution in milliliters?
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Answer:

84.8 mL

Explanation:

From the question given above, the following data were obtained:

Mass of CuNO₃ = 3.53 g

Molarity of CuNO₃ = 0.330 M

Volume of solution =?

Next, we shall determine the number of mole in 3.53 g of CuNO₃. This can be obtained as follow:

Mass of CuNO₃ = 3.53 g

Molar mass of CuNO₃ = 63.5 + 14 + (16×3)

= 63.5 + 14 + 48

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Mole of CuNO₃ =?

Mole = mass / Molar mass

Mole of CuNO₃ = 3.53 / 125.5

Mole of CuNO₃ = 0.028 moles

Next, we shall determine the volume of the solution. This can be obtained as follow:

Molarity of CuNO₃ = 0.330 M

Mole of CuNO₃ = 0.028 moles

Volume of solution =?

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0.330 × Volume = 0.028

Divide both side by 0.330

Volume = 0.028 / 0.330

Volume = 0.0848 L

Finally, we shall convert 0.0848 L to millilitres (mL). This can be obtained as follow:

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0.0848 L = 0.0848 L × 1000 mL / 1 L

0.0848 L = 84.8 mL

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