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2 years ago

What is the density of a 500g box whose volume is 67 ml?

Chemistry

1 answer:

Ivanshal [37]2 years ago

5 0

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 500 g

volume = 67 mL

We have

$density = \frac{500}{67} \\ = 7.462686$

We have the final answer as

Hope this helps you

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daser333 [38]

Answer:

Electric-Light-Heat

Explanation:

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4 years ago

Match the compounds as organic (O) or inorganic (I)..

zloy xaker [14]

Inorganic = H2O, NO2

Organic = C3H6, C22H24, CH4

3 0

3 years ago

Read 2 more answers

How many grams are in 2.5 moles of PO4?

Inessa05 [86]

94.971361 grams would be the answer

8 0

3 years ago

A quantity of 0.0250 mol of a gas initially at 0.050 L and 19.0°C undergoes a constant-temperature expansion against a constant

KiRa [710]

Answer:

$V_2=2.995L\\\\W=248.5J$

Explanation:

Hello,

In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

$P_1V_1=P_2V_2$

So we solve for $V_2$ by firstly computing the initial pressure:

$P_1=\frac{nRT}{V_1}=\frac{0.025mol*0.082\frac{atm*L}{mol*K}*(19+273.15)K}{0.050L} =11.98atm$

$V_2=\frac{P_1V_1}{P_2}=\frac{11.98atm*0.050L}{0.200atm}\\ \\V_2=2.995L$

Finally, we can compute the work by using the following formula:

$W=nRTln(\frac{V_2}{V_1} )=0.025mol*8.314\frac{J}{mol*K}*(19.0+273.15)K*ln(\frac{2.995L}{0.050L}) \\\\W=248.5J$

Best regards.

4 0

3 years ago

When the free-energy change (AG) of a reaction is negative, the reaction is said to be: Endergonic Non spontaneous Spontaneous E

Greeley [361]

Answer:

Spontaneous

Explanation:

For a spontaneous reaction , the value for the change in free energy or gibbs' free energy is negative .

The change in free energy , i.e. , ΔG , denotes the maximum amount of usable energy released , as going from initial state , i.e. , the reactant towards the final state , i.e. , the product .

And , the sign of the ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

ΔG < 0 , the reaction is Spontaneous

ΔG > 0 , the reaction is non Spontaneous

ΔG = 0 , the reaction is at equilibrium

For ,

ΔG < 0 , that the reaction proceed without any energy input , hence , it is Spontaneous in nature .

6 0

3 years ago