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blondinia [14]
2 years ago
15

What is the density of a 500g box whose volume is 67 ml?

Chemistry
1 answer:
Ivanshal [37]2 years ago
5 0

Answer:

<h2>7.46 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 500 g

volume = 67 mL

We have

density =  \frac{500}{67}  \\  = 7.462686

We have the final answer as

<h3>7.46 g/mL</h3>

Hope this helps you

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Hope this answers the question. Have a nice day.
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3 years ago
A measure of the kinetic energy of particle motion within a substance is temperature.
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A sample of N2 gas in a flask is heated from 27 Celcius to 150 Celcius. If the original gas is @ pressure of 1520 torr, what is
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Answer:

\large \boxed{\text{B.) 2.8 atm}}

Explanation:

The volume and amount are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ = 1520 Torr; T₁ =   27 °C

p₂ = ?;               T₂ = 150 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (  27 + 273.15) K = 300.15 K

T₂ = (150 + 273.15) K = 423.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{1520}{300.15} & = & \dfrac{p_{2}}{423.15}\\\\5.064 & = & \dfrac{p_{2}}{423.15}\\\\5.064\times423.15&=&p_{2}\\p_{2} & = & \text{2143 Torr}\end{array}\\

(c) Convert the pressure to atmospheres

p = \text{2143 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \textbf{2.8 atm}\\\\\text{The new pressure reading will be $\large \boxed{\textbf{2.8 atm}}$}

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3 years ago
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Answer:

4,572.67

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11 divided by 1000= 90.90

44= 11x

x=4

4 x 11= 4000

44-51.300=6.300

6.300 x 90.90=572.67

4000 + 572.67 = the answer

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Explanation:

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