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3 years ago

Draw a transition state for the reaction between ethyl iodide and sodium acetate

Chemistry

1 answer:

SCORPION-xisa [38]3 years ago

6 0

Transition state for the reaction between ethyl iodide and sodium acetateis shown below

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On the space shuttle, lithium hydroxide is produced from lithium oxide and water. The lithium hydroxide then reacts with the exh

Ratling [72]

Answer:

6,2g of CO₂

Explanation:

Based on the reactions:

Li₂O(s) + H₂O(g) → 2LiOH(s)

LiOH(s) + CO₂(g) → LiHCO₃(s)

2,6g of Li₂O and 1,3g of H₂O are:

2,6g × ( 1mol / 29,88g) = 0,087 moles

1.3g × ( 1mol / 18,01g) = 0,072 moles

That means limiting reactant is H₂O. The moles produced of LiOH are:

0,072 moles of H₂O × ( 2mol LiOH / 1mol H₂O) = 0,14 moles of LiOH

Thus, the maximum CO₂ that can react are 0,14 moles of CO₂, in grams

0,14 moles CO₂ × (44,01g / 1mol) = 6,2g of CO₂

I hope it helps!

6 0

3 years ago

On the galapagos islands, Darwin studied many creatures, including finches. Explain what he observed and how it relates to natur

Tatiana [17]

Darwin observed the beaks of the birds and how the different beaks helped the birds to eat different types of seeds.

This relates to natural selection because certain finches with say a smaller shorter beak would be able to eat only smaller seeds and fruits as to where a finch with a longer larger beak could eat larger bigger seeds and fruits.

Hope this helped! Have a great day!

5 0

3 years ago

What mass of silicon dioxide contains 9.72 X10e24 molecules of silicon dioxide?

dangina [55]

Answer:

1033.36g

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of SO2 also contains 6.02x10^23 molecules.

1 mole SO2 = 32 + (16x2) = 64g.

Now, If 64g of SO2 contains 6.02x10^23 molecules,

Therefore, Xg of SO2 will contain 9.72x10^24 i.e

Xg of SO2 = (64x9.72x10^24)/6.02x10^23

Xg of SO3 = 1033.36g.

Therefore, 1033.36g of SO2 contains 9.72x10^24 molecules

6 0

3 years ago

With 143.6 grams of acetylene and an excess amount of oxygen gas, what is the percent yeild of carbon dioxide if the actual yiel

nata0808 [166]

Answer:

93.28%

Explanation:

To solve the percent yield we need to find theoretical yield:

Percent yield = Actual Yield (452.78g) / Theoretical yield * 100

Theoretical yield is obtained converting the mass of acetylene to moles and using the balanced equation determine the moles of CO₂ produced assuming a 100% of reaction:

Moles acetylene (Molar mass: 26.04g/mol)

143.6g C₂H₂ * (1mol / 26.04g) = 5.515 moles C₂H₂

Moles CO₂:

5.515 moles C₂H₂ * (4 moles CO₂ / 2mol C₂H₂) = 11.029moles CO₂

Mass CO₂ (Molar mass: 44.01g/mol):

11.029moles CO₂ * (44.01g / mol) = 485.39g CO₂ is theoretical yield

Percent yield is:

Percent yield = 452.78g / 485.39g * 100

= 93.28%

8 0

3 years ago

Which of the following is NOT a property of gases?

Luda [366]

Answer:

a. Constant shape

8 0

2 years ago