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ollegr [7]
3 years ago
14

The mass of sample A is 100.0 g, then removed it from a graduated

Chemistry
1 answer:
yan [13]3 years ago
3 0

Answer: 25g/ml

Explanation:

Density = 100.0g/ 4.0mL = 25g/mL

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It is often necessary to prepare a dilute solution from a more concentrated solution rather than starting from a solid and just
valina [46]

Answer:

Take 10.0mL of your original solution and dilute it to 100.0mL and then, take 5.0mL of this solution and dilute it in another flask to 100.0mL

Explanation:

The initial solution of 0.3g of Red dye in 100mL has a concentration of:

0.3g Red dye × (1mol / 869g) = 3.4x10⁻⁴ mol Red Dye in 100mL = 0.100L:

3.4x10⁻⁴ mol / 0.1L = 3.4x10⁻³M

As you want a 1.7x10⁻⁵M solution, you need to dilute your solution:

3.4x10⁻³M / 1.7x10⁻⁵M = 200 times

Having this in mind, you must find the dilutions you must make to achieve the 200 of dilution factor (<em>Dilution factor is how many times you dilute a solution from a concetrated form).</em>

If you dilute the original solution taking 10.0mL to 100.0mL you dilute the solution: 100.0mL / 10.0mL = <em>10 times.</em>

Now, you need to dilute this solution another 20 times to achieve the 10*20 = 200 times of dilution.

If you take 5.0mL of the last solution and dilute it to 100.0mL you are diluting the solution 100.0mL / 5.0mL = <em>20 times.</em>

The dilution is:

3.4x10⁻³M × (10.0mL / 100.0mL) × (5.0mL / 100.0mL) = 1.7x10⁻⁵M

Thus, to obtain the 1.7x10⁻⁵M solutionyou need to:

<h3>Take 10.0mL of your original solution and dilute it to 100.0mL and then, take 5.0mL of this solution and dilute it in another flask to 100.0mL</h3>
8 0
3 years ago
Please tell me the answer I will mark you brainliest
Shkiper50 [21]

Answer:

3

Explanation:

third answer might be right

8 0
2 years ago
Read 2 more answers
What do people mean when they say everything is connected
NARA [144]
A network.. where one thing ends another begins
3 0
3 years ago
Percent Composition and Determining Empirical And Molecular Formulas
raketka [301]

Answer:

% comp. H = 2.8%, % comp. Cl = 97.2%

Explanation:

HCl mass = mass of H + mass of Cl

HCL mass = 1.00794 + 35.453 = 36.46094

% comp. of H = 1.007694 / 36.46094 x 100 = around 2.8% (2.76376308455)

% comp. of Cl = 35.453 / 36.46094 x 100 = around 97.2% (97.2355622208)

3 0
2 years ago
A water treatment plant applies chlorine for disinfection so that 10 mg/L chlorine is achieved immediately after mixing. The vol
Vlada [557]

<u>Answer:</u> The mass of chlorine needed by the plant per day is 9.4625\times 10^8mg

<u>Explanation:</u>

We are given:

Volume o water treated per day = 25,000,000 gallons

Converting this volume from gallons to liters, we use the conversion factor:

1 gallon = 3.785 L

So, \frac{3.785L}{1\text{ gallon}}\times 25,000,000\text{ gallons}=9.4625\times 10^7L

Amount of chlorine applied for disinfection = 10 mg/L

Applying unitary method:

For 1 L of water, the amount of chlorine applied is 10 mg

So, for 9.4625\times 10^7L of water, the amount of chlorine applied will be \frac{10mg}{1L\times 9.4625\times 10^7L}=9.4625\times 10^8mg

Hence, the mass of chlorine needed by the plant per day is 9.4625\times 10^8mg

6 0
3 years ago
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