Answer:
sample A
Explanation:
the first one because of the ppm value
Answer:
T2 = 260 K
Explanation:
<em>Given data:</em>
P1 = 150.0 k Pa
T1 = (-23+ 273.15) K = 250.15 K
V1 = 1.75 L
P2 = 210.0 kPa
V2 = 1.30 L
<em>To find:</em>
T2 = ?
<em>Formula:</em>
<em>Calculation:</em>
T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)
T2 = 260 K
Answer:
The answer to your question is Q = 355.64 J
Explanation:
Data
Heat = Q = ?
Temperature 1 = T1 = 20°C
Temperature 2 = T2 = 37°C
mass = m = 5 g
Specific heat = Cp = 4.184 J/g°C
Formula
Q = mCp(T2 - T1)
-Substitution
Q = (5)(4.184)(37 - 20)
-Simplification
Q = (5)(4.184)(17)
-Result
Q = 355.64 J
due to there reactive rate?
Answer: place a 2 in front of NaNo3 on left side of equation while leaving the other blanks empty or you can place a 1 in those blanks
Explanation:
Step 1 count and write down the amount of each given element for both sides
Step 2 begin placing numbers (coefficients) to each side to balance
