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vlada-n [284]
3 years ago
13

Don't know if this is for sure Chemistry but they didn't have just plain science

Chemistry
1 answer:
Elenna [48]3 years ago
7 0

B.Enviorment, Hope that helped

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Because that is the outer ring.
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During the water cycle, the sun's energy evaporates water from the surface of Earth. This water is the source of A) respiration.
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This water source is called precipitation
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Which statements correctly describe characteristics of cells? Check all that apply. A. Animal cells are all generally circular i
Gnoma [55]

Answer:

A. Correct

B. Wrong

C. Wrong.

D. Correct.

E. Correct.

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8 0
2 years ago
A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
3 years ago
A solution contains 0.775 g Ca2 0.775 g Ca2 in enough water to make a 1925 mL1925 mL solution. What is the milliequivalents of C
Romashka [77]

Answer: There will be 0.00002 meq per Liter of the solution.

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Normality=\frac{\text{no of gram equivalents} \times 1000}{\text{Volume in ml}}

Normality=\frac{\text{given mass}\times 1000}{\text {Equivalent mass}\times {\text{Volume in ml}}}

Equivalent weight is calculated by dividing the molecular weight by n factor.   {\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}

n= charge for charged species  , For Ca^{2+} , n =2

{\text{Equivalent weight}}=\frac{40}{2}=20g

\text{no of gram equivalents}=\frac{0.775g}{20g/mol}=0.04gramequivalents

Normality=\frac{0.04\times 1000}{1925}=0.02eq/L=0.00002meq/L

Thus there will be 0.00002 meq per Liter of the solution.

3 0
3 years ago
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