A. The patch's area in square kilometers (km²) is 1.61×10⁻⁹ km²
B. The cost of the patch to the nearest cent is 734 cents
<h3>A. How to convert 16.1 cm² to square kilometers (km²)</h3>
We can convert 16.1 cm² to km² as illustrated below:
Conversion scale
1 cm² = 1×10⁻¹⁰ km²
Therefore,
16.1 cm² = 16.1 × 1×10⁻¹⁰
16.1 cm² = 1.61×10⁻⁹ km²
Thus, 16.1 cm² is equivalent to 1.61×10⁻⁹ km²
<h3>B. How to determine the cost in cent</h3>
We'll begin by converting 16.1 cm² to in². This can be obtained as illustrated below:
1 cm² = 0.155 in²
Therefore,
16.1 cm² = 16.1 × 0.155
16.1 cm² = 2.4955 in²
Finally, we shall the determine the cost in centas fo r llow:
- Cost per in² = $2.94 = 294 cent
- Cost of 2.4955 in² =?
1 in² = 294 cent
Therefore,
2.4955 in² = 2.4955 × 294
2.4955 in² = 734 cents
Thus, the cost of the patch is 734 cents
Learn more about conversion:
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Jamuuj ExpertThe energy of a wave is directly proportional to the square of the waves amplitude. Therefore, E = A² where A is the amplitude. This therefore means when the amplitude of a wave is doubled the energy will be quadrupled, when the amplitude is tripled the energy increases by a nine fold and so on.Thus, in this case if the energy is 4J, then the amplitude will be √4 = 2 .
Answer:
t = 37.1 s
Explanation:
The equation for the reaction is given as;
2 N2O5(g) --> 4 NO2 + O2
Initial: 0.110 - -
change: -2x +4x +x
Final: 0.110 - 2x +4x +x
But final = 0.150atm;
0.110 - 2x + 4x + x = 0.150 atm
3x = 0.150 - 0.110
x = 0.0133 atm
Pressure in reactant side;
0.110 - 2x
0.110 - 2 (0.0133) = 0.0834 atm
The integral rate law expression is given as;
ln ( [A] / [Ao] ) = -kt
k = rate constant = 7.48*10^-3*s-1
ln (0.0834/0.11) = (7.48*10^-3) t
upon solving, t = 37.1 s
