1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ale4655 [162]
3 years ago
5

A single human body cell typically contains thousands of

Chemistry
1 answer:
Nitella [24]3 years ago
3 0
The answer to your question should be genes. 

You might be interested in
A solution of h2so4(aq) with a molal concentration of 2.24 m has a density of 1.135 g/ml. what is the molar concentration of thi
OLga [1]
This problem is simply converting the concentration from molality to molarity. Molality has units of mol solute/kg solvent, while molarity has units of mol solute/L solution.

2.24 mol H2SO4/kg H2O * (0.25806 kg H2SO4/mol H2SO4) = 0.578 kg H2SO4/kg H2O

That means the solution weighs a total of 1 kg + 0.578 kg = 1.578 kg. Then, convert it to liters using the density data:

1.578 kg * (1000g / 1kg) * (1 mL/1.135 g) = 1390 mL or 1.39 L.

Hence, the molarity is

2.24/1.39 = 1.61 M
7 0
3 years ago
If 500ml of H₂ gas at 600mmHg and 400ml of CO₂ gas at 700mmHg are mixed in a 1 lit vessel, find the total pressure of mixture of
seraphim [82]

Answer:

Total pressure increased

Explanation:

When gas C is added in the vessel then number of mole increases and number of collision depends on the number of molecules present in the vessel and on adding gas C ,mole also increases hence  number of collision increases therefore pressure also increases because number of collision increases.

Total pressure increases.

6 0
2 years ago
Hospital patients are administered oxygen from an pressurized
Nataly_w [17]

Answer:

110L

Explanation:

Boyle's Law states that P1×V1=P2×V2

Volume is indirectly proportional to Pressure so P×V is constant

P1=55atm

V1=6L

P2=3atm

V2 is to be found

P1×V1=P2×V2

6×55=3×V2

330=3×V2

Answer: V2=110L

8 0
3 years ago
This question has two parts btw
Oxana [17]

Answer:

the cold one is going to have a faster reaction time

Explanation:

5 0
3 years ago
Read 2 more answers
Calculate the moles and grams of solute in each solution. D. 2.0 L of 0.30M Na2SO4. I already have A, B, and C. Thanks!
e-lub [12.9K]
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol


Find the molar mass
2Na = 23 * 2 = 46 grams
1S   = 32 * 1 = 32 grams
O4   = 16 * 4 = 64 grams
Total =            142 grams / mol

Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???

given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams. 

85.2 are in a 2 L solution that has a concentration of 0.6 mol/L


4 0
3 years ago
Read 2 more answers
Other questions:
  • Recycling of aluminum cans is an example of A) increasing entropy is a nonspontaneous process B) decreasing entropy is a nonspon
    14·1 answer
  • In one kind of nuclear reaction, two nuclei fuse, or join together, to form a larger nucleus. This kind of reaction happens only
    14·1 answer
  • The substance gray tin is found to crystallize in a cubic lattice, with an edge length of 646.0 pm. if the density of solid gray
    7·1 answer
  • You are looking at an atom that has the atomic number of 7 and an atomic mass of 16. how many neutrons are there in this atom?
    13·1 answer
  • What is necssesary for a plant to exhibit phototropism
    8·1 answer
  • Please help me with this question. <br> Thank you.
    14·2 answers
  • How does chemical change affect the composition of matter
    14·1 answer
  • Before using glassware in the lab, it is important to _______.
    12·2 answers
  • Finish the attachment quick it's due pleaseee
    7·1 answer
  • Select the correct answer. if two half-lives have passed since a scientist collected a 1.00-gram sample of u-235, how much u-235
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!