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3 years ago

What is the Doppler Effect?

1 answer:

8 0

<span>an increase (or decrease) in the frequency of sound, light, or other waves as the source and observer move toward (or away from) each other. The effect causes the sudden change in pitch noticeable in a passing siren, as well as the redshift seen by astronomers.

Hope this helps :D</span>

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How can the momentum of an object be changed?

pickupchik [31]

C. You’re welcome

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4 years ago

1-Autotrophic plants are also called

tresset_1 [31]

Answer:

1. Producers

2. cell (guards)

3. Rhizobium

4. Rafflesia Arnoldii

5. Xylem

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3 years ago

A bob of mass m = 0.250 kg is suspended from a fixed point with a massless string of length L = 22.0 cm. You will investigate th

katen-ka-za [31]

To solve the problem, it is necessary to use the concepts of gravitational force, centripetal force and trigonometric components that can be extrapolated from the statement.

By definition we know that the Force of Gravity is given by

$F_g=mg$

Where,

m= Mass

g = Gravitational Acceleration

The centripetal force is given by,

$F_c = \frac{mv^2}{R}$

Where,

m = Mass

v = Velocity

R = Radius

For the case described in the problem, the Force of gravity the net component would be given by sin?, While for the centripetal force the net component is in the horizontal direction, therefore it corresponds to the $cos\theta$

Then,

$F_g = mg sin\theta$

$F_c = \frac{mv^2}{r}cos\theta$

From the radius we have its length but not the net height, which would be given by

$r = L sin\theta$

So equating the equations we have to

$F_g = F_c$

$mg sin\theta=\frac{mv^2}{r}cos\theta$

$mg sin\theta=\frac{mv^2}{Lsin\theta}cos\theta$

Re-arrange to find v,

$v = \sqrt{\frac{gLsin^2\theta}{cos\theta}}$

Replacing with our values

$v = \sqrt{\frac{(9.8)(22*10^{-2})(sin^2 24)}{cos24}}$

$v = 0.624$

Therefore the tangential velocity of the mass is 0.624m/s

5 0

4 years ago

A 4.00-kg model rocket is launched, expelling 64.0 g of burned fuel from its exhaust at a speed of 675 m/s. What is the velocity

olga_2 [115]

Answer:

The velocity of the rocket is 7.8 m/s

Explanation:

3 0

3 years ago

A seagull flying horizontally over the ocean at a constant speed of 2.60 m/s carries a small fish in its mouth. It accidentally

Ivenika [448]

(a) +2.60 m/s

The motion of the fish dropped by the seagul is a projectile motion, which consists of two independent motions:

- a horizontal uniform motion, at constant speed

- a vertical motion, at constant acceleration (acceleration of gravity, $g=-9.8 m/s^2$ , downward)

In this part we are only interested in the horizontal motion. As we said the horizontal component of the fish's velocity does not change, therefore its value when the fish reaches the ocean is equal to its initial value, which is the speed at which the seagull was flying (because it was flying horizontally):

$v_x = +2.60 m/s$

(b) -17.2 m/s

The vertical component of the fish's velocity instead follows the equation:

$v_y = u_y +gt$

where

$u_y = 0$ is the initial vertical velocity, which is zero

$g=-9.8 m/s^2$ is the acceleration of gravity

t is the time

Since the fish reaches the ocean at t = 1.75 s, we can substitute this time into the formula to find the final vertical velocity:

$v_y = 0+(-9.8)(1.75)=-17.2 m/s$

where the negative sign indicates the direction (downward).

(c)

The horizontal component of the fish's velocity would increase

The vertical component of the fish's velocity would stay the same.

As we said from part (a) and (b):

- The horizontal component of the fish's velocity is constant during the motion and it is equal to the initial velocity of the seagull -> so if the seagull's initial speed increases, the horizontal velocity of the fish will increase too

- The vertical component of the fish's velocity does not depend on the original speed of the seagull, therefore it is not affected.

4 0

3 years ago