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4 years ago

CRIMINOLOGY

Physics

1 answer:

lbvjy [14]4 years ago

5 0

Answer:

<h3>Two-track correctional system is a system of consisting two correctional institutions for criminals.</h3>

Explanation:

The two-track correctional system is a correctional system that consists of two separate correctional institutions for criminals. One institution for juveniles and one for adult criminals.
No, two-track correctional system would not work better in our country. There are many cases of serious juvenile crimes in our country. Juveniles who commit serious or atrocious crimes should be dealt strictly in an adult or criminal court without exemption.
Yes, this would reduce the percentage of offenders re-entering the system because juveniles incarcerated for serious crimes would be locked up in the prison instead of being acquitted after a short detention.
This would stop them from committing similar offences and would reduce potential crimes from ex-convicted juveniles.

You might be interested in

А masd<br>Of 500kg a raised to a height of 6m In 30s<br>Find (a) Workdone .

Mazyrski [523]

Answer:

Work done is 882000joule.

power is 29400watt.

Explanation:

given,

Mass(m)=500kg

Acceleration due to gravity(g)=9.8m/s²

Height(h)=6m

Time taken(t)=30s

Workdone=?

Power=?

now,

workdone=force*displaxement

= m*g*h

=500*9.8*6

=8,82,000joule

so, the work done by the man is 8,82,000joule.

then,

power=workdone/time taken

=8,82,000/30

=29,400watt

so, the required power to lift a load is 29,400watt.

5 0

3 years ago

(a) The Eskimo pushes the same 50.0-kg sled over level ground with a force of 1.75 102 N exerted horizontally, moving it a dista

vivado [14]

Answer: 0.306

Explanation:

from the question we are given the following

mass of sled (m) = 50 kg

force (f) = 1.75 x 10^2 N = 175 N

distance (s) = 6 m

net work done on the sled = 1.50 x 10 ^2 N = 150 N

acceleration due to gravity (g) = 9.8 m/s^2

coefficient of friction = μ

lets first calculate the frictional force (ff)

ff = μ x m x g = μ x 50 x 9.8 = 490 μ

work done on the slide by the applied force (W1)= f x s = 175 x 6 = 1050 j

work done on the slide by frictional force (W2) = ff x s = 490 μ x 6 = 2940μ j

now the net work done is the work done by the frictional force subtracted from the work done by the applied force

net work done = W1 - W2

150 = 1050 - 2940μ

2940μ = 1050 - 150

μ = 900 / 2940

μ = 0.306

3 0

3 years ago

11.) If figure skater spins with a circular acceleration of 275 m/s^2 in a circle 5 poin with a radius of 0.55 meters, calculate

DaniilM [7]

Answer:

we don't care what ure saying thats absurd

7 0

3 years ago

The diagram shows a compressed spring between two carts initially at rest on a horizontal frictionless surface. Cart A has a

EastWind [94]

Answer:

momentum

Explanation:

the impulse is equal for both carts, the momentum for both carts is zero both before the string is cut and after it is cut

6 0

3 years ago

A beam of light in air is incident at an angle of 30º to the surface of a rectangular block of clear plastic (n = 1.46). The lig

Aneli [31]

Answer:

θ = 30°

Explanation:

Firts, the angle when the beam of light passes through the block cam be calculated using Snell Law:

$n_{1}sin(\theta_{1}) = n_{2}sin(\theeta_{2})$

<u>Where</u>:

n₁: is the index of refraction of the incident medium (air) = 1

θ₁: is the incident angle = 30°

n₂: is the medium 2 (plastic) = 1.46

θ₂: is the transmission angle

Hence, θ₂ is:

$sin(\theta_{2}) = \frac{n_{1}*sin(\theta_{1})}{n_{2}} = \frac{1*sin(30)}{1.46} = 0.34 \rightarrow \theta_{2} = 20.03 ^{\circ}$

Now, when the beam of light re-emerges from the opposite side, we have:

n₁: is the index of refraction of the incident medium (plastic) = 1.46

θ₁: is the incident angle = 20.03°

n₂: is the medium 2 (air) = 1

θ₂: is the transmission angle

Hence, the angle to the normal to that surface (θ₂) is:

$sin(\theta_{2}) = \frac{n_{1}*sin(\theta_{1})}{n_{2}} = \frac{1.46*sin(20.03)}{1} = 0.50 \rightarrow \theta_{2} = 30 ^{\circ}$

Therefore, we have that the beam of light will come out at the same angle of when it went in, since, it goes from air and enters to a plastic medium and then enters again in this medium to go out to air again. This was proved using the Snell Law.

I hope it helps you!

5 0

3 years ago