The gravitational force between two objects is given by:

where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation
In this problem, the first object has a mass of

, while the second "object" is the Earth, with mass

. The distance of the object from the Earth's center is

; if we substitute these numbers into the equation, we find the force of gravity exerted by the Earth on the mass of 0.60 kg:
Hooke's Law says that F=-kx where k is the spring constant measured in N/m (newtons per meter)
Answer:
34 m/s
Explanation:
m = Mass of glider with person = 680 kg
v = Velocity of glider with person = 34 m/s
= Mass of glider without person = 680-60 kg
= Gliders speed just after the skydiver lets go
= Mass of person = 60 kg
= Velcotiy of person = 34 m/s
As the linear momentum of the system is conserved

The gliders speed just after the skydiver lets go is 34 m/s
B. Ptolemy believed that the earth was the center of the universe