Ask question

Ask question

All categories

3 years ago

9

A police car is rapidly approaching you at a stop light. Explain what happens to the frequency of the sound as the police car dr

aws closer. What do you hear?

1 answer:

viva [34]3 years ago

7 0

When the police car is moving towards you, the sound waves are more compressed together, leading to a higher pitch sound. This is according to the Doppler Effect, in which sound waves ahead of the object is more compressed, leading to a higher pitch, and more spread out behind, leading to a lower pitch.

hope this helps

You might be interested in

A .025 kg bullet is moving at 350 m/s when it hits and then passes through a 7 kg block of wood. After the bullet passes through

slamgirl [31]

Answer:

The final velocity of the wooden block is equal to $1.035 m/s$

Explanation:

Given that mass of bullet = $m_{b} = 0.025kg$

Mass of wood = $m_{w} = 7kg$

Initial velocity of bullet = $u_{b} = 350m/s$

Final velocity of bullet = $v_{b} = 60m/s$

Initial velocity of wood = o

Final velocity of wood = $v_{w]$

Here momentum is conserved so initial momentum = final momentum

$m_{b}u_{b} = m_{b} v_{b} + m_{w}v_{w}$ .

Upon substituting these values in above equation , we get

$v_{w} = 1.035m/s$ .

7 0

3 years ago

As a mercury atom absorbs a photon of

Allisa [31]

The energy absorbed by photon is 1.24 eV.
This is the perfect answer.

8 0

3 years ago

The Sun is about 150 million km from earth. how long does it take light from the sun to reach earth? (Speed of light is 3x10^8m/

madam [21]

Time =      (distance) / (speed)

Time = (150 x 10⁹ m) / (3 x 10⁸ m/s) =

   50 x 10¹ sec =

       <em>500 sec</em> = 8 min 20 sec

3 0

3 years ago

How many moles are in 95 g of Na?

nexus9112 [7]

1.8 mol of Na. hope this helps

3 0

3 years ago

Read 2 more answers

The electric field between two parallel plates is uniform, with magnitude 628 N/C. A proton is held stationary at the positive p

aliina [53]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Data Given:

Electric Field between two parallel plates = 628 N/C

Separation = 4.22 cm

a) In this part, we are asked to calculate the distance from positive plate at which the electron and proton pass each other.

Solution:

First of all:

Force on proton due to the Electric field between the plates is:

$F_{p}$ = $q_{p}$ E

and, we know that, F = ma

So,

$m_{p}$ a = $q_{p}$ E

a = $\frac{q_{p}.E }{m_{p} }$ Equation 1

So,

The distance covered by the electron is:

S = ut + 1/2 $at^{2}$

Here, u = 0.

S = 1/2 $at^{2}$

Put equation 1 into the above equation:

S = 1/2 x ( $\frac{q_{p}.E }{m_{p} }$ ) $t^{2}$ Equation 2

So,

Similarly, the distance covered by electron will be:

(D-S) = 1/2 x ( $\frac{q_{e}.E }{m_{e} }$ ) $t^{2}$ Equation 3

We know that the charge of electron is equal to the charge of proton so,

$q_{p}$ = $q_{e}$ = q

By dividing the equation 2 by equation 3, we get:

$\frac{S}{D-S}$ = $\frac{m_{e} }{m_{p} }$

Solve the above equation for S,

S $m_{p}$ = $m_{e}$ D - $m_{e}$ S

So,

S = $\frac{m_{e}.D }{(m_{e} + m_{p}) }$

Plugging in the values,

As we know the mass of electron is 9.1 x $10^{-31}$ and the mass of proton is 1.67 x $10^{-27}$

S = $\frac{9.1 . 10^{-31} . 4.22 }{(9.1 . 10^{-31} + 1.67 . 10^{-27} }$

S = 0.002298 cm (Distance from the positive plate at which the two pass each other)

b) In this part, we to calculate distance for Sodium ion and chloride ion as above.

So,

we already have the equation, we need to put the values in it.

So,

S = $\frac{m_{Cl}.D }{(m_{Cl} + m_{Na}) }$

As we know the mass of chlorine is 35.5 and of sodium is 23

S = $\frac{35.5 . 4.22}{(35.5 + 23)}$

S = 2.56 cm

7 0

2 years ago