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3 years ago

Brainliest for correct answer! :)

Physics

1 answer:

Katena32 [7]3 years ago

5 0

Answer:

1. 300.15

2. 873.15

3. 221.95

1. -243.15

2. -210.85

3. 295.17

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Jack has two boxes: one is 148g and one is 78g. if jack pushes both boxes with the same amount of force which will accelerate fa

kifflom [539]

1) A The 78g
2) C Push on the wagon in the opposite direction as Jack with a force that is the same as Jack is applying.

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3 years ago

A ball is thrown upward. As it passes 5.0 m height it is traveling at 4.0 m/s up. What was its initial upward velocity? (a) 7.0

sveticcg [70]

Answer:

c) 10.7m/s

Explanation:

From the exercise we know that at 5m the ball is traveling at 4m/s

To calculate its initial velocity we need to solve the following equation:

$v_{y}^{2}=v_{oy}^{2}+2g(y-y_{o})$

Since the initial height is 0

Solving for $v_{o}$

$v_{oy}=\sqrt{v_{y}^{2}-2gy}=\sqrt{(4m/s)^2-2(-9.8m/s^2)(5m)}=10.7m/s$

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3 years ago

Difference between male and female gamete

Inga [223]

Answer:

The male gamete is smaller in comparison to that of the female gamete.

The male gamete is conical from the front while the female gamete is spherical.

The cytoplasm in the male gamete is less in comparison to that of the female gamete.

The male gamete can move with the help of the tail while the female gametes are immobile and do not have any tail or flagella present.

The number of mitochondria present in the sperm is less than the number of mitochondria present in the ovum.

The male gamete has acrosome present in the head region that contains enzymes for dissolving the membranes present around the ovum. The ovum does not contain such digestive enzymes.

Explanation:

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3 years ago

Read 2 more answers

What is the magnitude of electrical force of attraction between an copper nucleus (29 protons) and its innermost electron if the

Agata [3.3K]

The charge of the copper nucleus is 29 times the charge of one proton:
$Q=29 q= 29 \cdot 1.6 \cdot 10^{-19}C=4.64 \cdot 10^{-18}C$
the charge of the electron is
$e=-1.6 \cdot 10^{-19}C$
and their separation is
$r=1.0 \cdot 10^{-12} m$

The magnitude of the electrostatic force between them is given by:
$F=k_e \frac{Qe}{r^2}$
where $k_e$ is the Coulomb's constant. If we substitute the numbers, we find (we can ignore the negative sign of the electron charge, since we are interested only in the magnitude of the force)
$F=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(4.64 \cdot 10^{-18}C)(1.6 \cdot 10^{-19}C)}{(1.0 \cdot 10^{-12} m)^2}=6.68 \cdot 10^{-3} N$

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3 years ago

A material you are testing conducts electricity but canot be pulled into wires

agasfer [191]

A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a metalloid. Hope this helps!

4 0

4 years ago