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Marta_Voda [28]
3 years ago
11

Select all that apply. What factors can limit growth?

Physics
2 answers:
Rudiy273 years ago
8 0
A, b and d

Competition for fix resources of course increases the energy expenditure needed to gather those resources and leaves less for a given population. A lower amount of sunlight or water also contributes to decreased energy which lowers growth. Finally, small borders limit growth in that population density can only go so high before the death rate increases beyond the birth rate.
Ugo [173]3 years ago
7 0

Answer:

a b and d plz vote brainliest need 1 more for a higher rank up

Explanation:

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The weight of the car in the picture of the computer screen is 9,800 Newton's.

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Why do elements within a group have similar chemical properties
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4 0
3 years ago
Select the correct statement to describe when a sample of liquid water vaporizes into water vapor
sweet-ann [11.9K]

Answer:

This procces is called evaporation.

Explanation:

When you have liquid water that is transformed into steam, a phase change is called evaporation. The temperature for the evaporation of water depends on the pressure, for example for water at atmospheric pressure the temperature of evaporation is equal to 100°C. as the pressure increases are achieved evaporation temperatures higher. When that happens, the phase change temperature of the water is not increasing, as the process that takes place is the transfer of latent heat and applies only to changes of phase, that is to say at atmospheric pressure when it has 100% of the steam this will be at 101°C.

8 0
4 years ago
Determine the acceleration due to gravity for low Earth orbit (LEO) given: MEarth = 6.00 x 1024 kg, rEarth = 6.40 x 106 m, G = 6
Nana76 [90]

Answer:

The answer to the question is as follows

The  acceleration due to gravity for low for orbit is  9.231 m/s²

Explanation:

The gravitational force is given as

F_{G}= \frac{Gm_{1} m_{2}}{r^{2} }

Where F_{G} = Gravitational force

G = Gravitational constant = 6.67×10⁻¹¹\frac{Nm^{2} }{kg^{2} }

m₁ = mEarth = mass of Earth = 6×10²⁴ kg

m₂ = The other mass which is acted upon by  F_{G} and = 1 kg

rEarth = The distance between the two masses = 6.40 x 10⁶ m

therefore at a height of 400 km above the erth we have

r = 400 + rEarth = 400 + 6.40 x 10⁶ m = 6.80 x 10⁶ m

and  F_{G} = \frac{6.67*10^{-11} *6.40*10^{24} *1}{(6.8*10^{6})^{2} } = 9.231 N

Therefore the acceleration due to gravity =  F_{G} /mass  

9.231/1 or 9.231 m/s²

Therefore the acceleration due to gravity at 400 kn above the Earth's surface is  9.231 m/s²

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