Answer:
13 m/s
Explanation:
The computation of the final velocity is shown below;
We know that
v^2 = u^2 + 2as
Here v represent the final velocity
u denotes the initial velocity
a denotes the acceleration
And, s denotes the displacement
So, the final velocity is
v^2 = (5)^2 + 2(8)(9)
= sqrt(25 + 144)
= sqrt(169)
= 13 m/s
Answer:
synthesis is correct answer.
Answer:
Explanation:
capacitance of sphere 2 will be 4.5 times sphere 1
a ) when spheres are in contact they will have same potential finally . So
V_1 / V_2 = 1
b )
Charge will be distributed in the ratio of their capacity
charge on sphere1 = q x 1 / ( 1 + 4.5 )
= q / 5.5
fraction = 1 / 5.5
c ) charge on sphere 2
= q x 4.5 / 5.5
fraction = 4.5 / 5.5
d ) surface charge density of sphere 1
= q /( 5.5 x A ) where A is surface area
surface charge density of sphere 2
= q x 4.5 /( 5.5 x 4.5² A ) where A is surface area
= q /( 5.5 x 4.5 A )
q_1/q_2 = 4.5
I’m lost at this question, sorry but I would’ve help !
Answer:
The effort distance (also sometimes called the “effort arm”) is shorter than the resistance distance. Mechanical advantage = |Fr/Fe | where | means “absolute value.” Mechanical advantage is always positive.
