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Marta_Voda [28]
3 years ago
11

Select all that apply. What factors can limit growth?

Physics
2 answers:
Rudiy273 years ago
8 0
A, b and d

Competition for fix resources of course increases the energy expenditure needed to gather those resources and leaves less for a given population. A lower amount of sunlight or water also contributes to decreased energy which lowers growth. Finally, small borders limit growth in that population density can only go so high before the death rate increases beyond the birth rate.
Ugo [173]3 years ago
7 0

Answer:

a b and d plz vote brainliest need 1 more for a higher rank up

Explanation:

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1. Meiosis produces daughter cells that are
Marina86 [1]

Answer:

1. A Haploid

2. A. Somatic Cell production

3. B. Gametic cell production

4. C. Mitosis produces identical cells to parent cells.

5. B 4:0

6. C Both parent bees are heterozygous Ll

7. D DNA is made up of chromosomes

8. B Each hypothesis was tested and DNA supported the data better

9. D There may be an increase in pest populations that are resistant to control measures.

10. A They are proven to cause cancer.

11. B a form of a gene

Explanation:

Answer was too long, so is attached in a word document

Download docx
5 0
3 years ago
A 500 μF capacitor is wired in series with a 5 V battery and a 20 kΩ resistor. What is the voltage across the capacitor after 20
liq [111]

Answer:

Explanation:

It is a question relating to charging of capacitor . For charging of capacitor , the formula is as follows.

Q = CV ( 1 - e^{-\lambda\times t} )

λ = 1/CR , C is capacitance and R is resistance.

= 1/(500 x 10⁻⁶ x 20 x 10³ )

= .1

λ t = .1 x 20

λ t = 2

CV = 500 X 10⁻⁶ X 5

= 2500 X 10⁻⁶ C

Q = 2500 x 10⁻⁶ ( 1 - e^{-2} )

= 2500 x 10⁻⁶ x .86566

= 2161.66 μ C .

voltage = Charge / capacitor

2161.66 μ C  / 500μ F

= 4.32 V

3 0
4 years ago
Read 2 more answers
A string or rope will break apart if it is placed under too much tensile stress. Thicker ropes can withstand more tension withou
Lemur [1.5K]

Answer: The answer is 13.02 meter

Explanation: your question is incomplete, the complete question is this if A string or rope will break apart if it is placed under too much tensile stress. Thicker ropes can withstand more tension without breaking because the thicker the rope, the greater the cross-sectional area and the smaller the stress. One type of steel has a density of

7750kg/m3 and will break if the tensile stress exceeds 7.0×108N/m2.

You want to make a guitar string from a mass of 4.5 g of this type of steel. In use, the guitar string must be able to withstand a tension of 900 N without breaking. Your job is the following.

(a) Determine the maximum length the string can have

Answer:

As we know that density(p)= mass(m)/volume(V)

Solve for volume(V)= mass/density

If the given mass value is in gram then we have to divide it by 1000 to get the value in kilogram so our mass in kg will be 3.7/1000= 0.0037 kg

And if density is in kg/m^3

Then volume will be V= 0.0037/7730 =>

4.79^10-7m^3

Now we know that stress = Force/Area

For Area = force/stress => 900/7*10^8=> 2795.95m^2

For length= volume/Area => 4.79^10-7/2795.95

Length= 13.02 m

4 0
3 years ago
Why are wheels and steam engine important in the history of transport​
STALIN [3.7K]

Explanation:

Because it's a power to turn the wheels of industry

5 0
3 years ago
Suppose that the sound level of a conversation is initially at an angry 71 dB and then drops to a soothing 54 dB. Assuming that
Goryan [66]

Answer:

Explanation:

In the decibel scale , intensity of sound changes logarithmically as follows

10log\frac{I}{I_0} = Value in decibel scale , the value of I₀ = 10⁻¹² W /m².

Putting the values

10log\frac{I}{10^{-12}} = 71

log\frac{I}{10^{-12}} = 7.1

\frac{I}{10^{-12}} = 10^{7.1}

I= 10^{-4.9} W/m²

Similarly for 54 dB sound intensity can be given as follows

I = 10⁻¹² x 10^{5.4}

I= 10^{-6.6 } W / m²

For intensity of sound the relation is as follows

I = 2π²υ²A²ρc where υ is frequency , A is amplitude , ρ is density of air and c is velocity of sound .

Putting the given values for 71 dB

I= 10^{-4.9}  = 2π² x 504²xA²x 1.21 x  346

A² = 60.03 x 10⁻¹⁶

A = 7.74 x 10⁻⁸ m

For 54 dB sound

10^{-6.6} = 2π² x 504²xA²x 1.21 x  346

A² = 1.1978 x 10⁻¹⁶

A = 1.1 x 10⁻⁸ m

6 0
3 years ago
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