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ivann1987 [24]
3 years ago
7

Relative density of mercury is 13600 what does it mean

Physics
1 answer:
zvonat [6]3 years ago
8 0

Answer:

relative density is the density divided by some reference density.

for liquids like mercury the reference density is most likely water, so

relative density = density mercury / density of water = 13600

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A pure substance is chemically combined

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All elements are pure substances, along with tin, diamond, and etc...
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The student throws one cannonball directly upward at 5.0 m/s and simultaneously throws the other cannonball directly downward at
Mademuasel [1]
Let the cannonball be thrown at a height of h above ground.
Then  the potential energy of the ball is
V = m*g*h
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Also, the kinetic energy of the ball is
K = (1/2)mu²
where
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where V = vertical velocity when the ball strikes the ground.

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Answer: There is no difference.
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4 years ago
}Un alumno utiliza una balanza de dos platillos y coloca un objeto en el platillo derecho. Luego coloca las masas patrón en el i
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3 years ago
When two trains, going in opposite directions, are passing on tracks that are laid out close together, the train cars can often
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<h3>Answer:</h3>

"<u>Therefore, the speed of the air decreases, the pressure acting on the two trains increases (by Bernoulli's principle), and the two trains lean in toward one another</u>."

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A bicycle is traveling with a speed of 12 m/s. The cyclist hits the brakes reducing the speed to 4 m/s in a time of 4.8 seconds.
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So, the acceleration of the bicycle is approximately <u>-1.67 m/s²</u> or it can be said to be decelerating approximately <u>1.67 m/s²</u>.

<h3>Introduction</h3>

Hi ! Here I will help material about linear motion changes regularly, which is where you will hear a lot of the term acceleration. Acceleration occurs when an object's speed increases in a certain time interval. Acceleration can be negative which is called deceleration. The relationship between acceleration with velocity and time is manifested in the equation:

\boxed{\sf{\bold{a = \frac{v_2 - v_1}{t}}}}

With the following conditions :

  • a = acceleration (m/s²)
  • \sf{v_2} = object's final velocity (m/s)
  • \sf{v_1} = object's initial velocity (m/s)
  • t = interval of the time (s)

<h3>Problem Solving </h3>

We know that :

  • \sf{v_2} = object's final velocity = 4 m/s
  • \sf{v_1} = object's initial velocity = 12 m/s
  • t = interval of the time = 4.8 s

What was asked :

  • a = acceleration = ... m/s²

Step by step :

\sf{a = \frac{v_2 - v_1}{t}}

\sf{a = \frac{4 - 12}{4.8}}

\sf{a = \frac{-8}{4.8}}

\boxed{\sf{a \approx -1.67 \: m/s^2}}

So, the acceleration of the bicycle is about -1.67 m/s² or it can be said to be decelerating around 1.67 m/s².

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