Answer:
Static Friction-Friction that acts when the two objects are not moving
Sliding Friction-Two solid surfaces slide across each other
Rolling Friction-An object rolls across each other
Fluid Friction-Friction that occurs as an object moves through a fluid
Explanation:
Answer:
i) 21 cm
ii) At infinity behind the lens.
iii) A virtual, upright, enlarged image behind the object
Explanation:
First identify,
object distance (u) = 42 cm (distance between object and lens, 50 cm - 8 cm)
image distance (v) = 42 cm (distance between image and lens, 92 cm - 50 cm)
The lens formula,
Then applying the new Cartesian sign convention to it,
Where f is (-), u is (+) and v is (-) in all 3 cases. (If not values with signs have to considered, this method that need will not arise)
Substituting values you get,
i) 
f = 21 cm
ii) u =21 cm, f = 21 cm v = ?
Substituting in same equation
v ⇒ ∞ and image will form behind the lens
iii) Now the object will be within the focal length of the lens. So like in the attachment, a virtual, upright, enlarged image behind the object.
Answer:
medium
Explanation:
A substance or particle that wave travel through is called medium. There are two main types of such medium, some contains particles and some are vacuums.
- Waves can travel through a vacuum which contains no particles.
- Some can also contain particles.
- Waves can interact in different ways with the medium.
An additional 10ppm of methane will change the upward IR heat flux (in tropical
atmosphere) from 289.29 W/m2
to 286.211 W/m2
, which is a reduction of 3.08
W/m2
.
An additional 10ppm of CO2 will change the upward IR heat flux from 289.29 W/m2
to 289.29 W/m2
, which is a change of 0.13 W/m2
.
Therefore, an additional 10 ppm of methane would have a much larger impact on
the outgoing infrared flux than an additional 10 ppm of CO2 at current
concentrations
