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3 years ago

In the diagram, each charge is

Physics

1 answer:

Jlenok [28]3 years ago

3 0

Answer:

Quick maths

First you find the fafarick and the lalickc and the caprisum and the joinnt

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The frequency of a physical pendulum comprising a nonuniform rod of mass 1.15 kg pivoted at one end is observed to be 0.658 Hz.

S_A_V [24]

Answer:

The rotational inertia of the pendulum around its pivot point is $0.280\,kg\cdot m^{2}$ .

Explanation:

The angular frequency of a physical pendulum is measured by the following expression:

$\omega = \sqrt{\frac{m\cdot g \cdot d}{I_{o}} }$

Where:

$\omega$ - Angular frequency, measured in radians per second.

$m$ - Mass of the physical pendulum, measured in kilograms.

$g$ - Gravitational constant, measured in meters per square second.

$d$ - Straight line distance between the center of mass and the pivot point of the pendulum, measured in meters.

$I_{O}$ - Moment of inertia with respect to pivot point, measured in $kg\cdot m^{2}$ .

In addition, frequency and angular frequency are both related by the following formula:

$\omega =2\pi\cdot f$

Where:

$f$ - Frequency, measured in hertz.

If $f = 0.658\,hz$ , then angular frequency of the physical pendulum is:

$\omega = 2\pi \cdot (0.658\,hz)$

$\omega = 4.134\,\frac{rad}{s}$

From the formula for the physical pendulum's angular frequency, the moment of inertia is therefore cleared:

$\omega^{2} = \frac{m\cdot g \cdot d}{I_{o}}$

$I_{o} = \frac{m\cdot g \cdot d}{\omega^{2}}$

Given that $m = 1.15\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ , $d = 0.425\,m$ and $\omega = 4.134\,\frac{rad}{s}$ , the moment of inertia associated with the physical pendulum is:

$I_{o} = \frac{(1.15\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.425\,m)}{\left(4.134\,\frac{rad}{s} \right)^{2}}$

$I_{o} = 0.280\,kg\cdot m^{2}$

The rotational inertia of the pendulum around its pivot point is $0.280\,kg\cdot m^{2}$ .

8 0

3 years ago

The steps in the scientific process must be followed in order. True False

olya-2409 [2.1K]

Answer: True

Hope I helped :)

5 0

2 years ago

Read 2 more answers

What is the minimum force required to life a 50-N load with one fixed pulley?'

IRINA_888 [86]

One fixed pulley doesn't change the strength of the force that
pulls on the rope. The pulley only changes its direction. So,
to lift a 50-N load, you need to pull on the rope with at least 50-N .

8 0

3 years ago

Passengers in a high-flying jumbo jet feel their normal weight in flight, while passengers in an orbiting space vehicle do not,

daser333 [38]

Answer:E none of the above

Explanation:

When a space shuttle orbiting around the earth then earth gravitational force keeps the shuttle in its orbit by providing centripetal force. Tangential velocity makes the shuttle to revolve around the earth. Earth gravitational pull is significant to make the shuttle move in orbit while the Passengers feel weightlessness because they are falling downward but never able to reach as they move fast enough such that earth curves away them.

4 0

3 years ago

A force of 15 newtons is applied to both Object A with a mass of 25 kilograms and Object B with a mass of 50 kilograms. What is

Aleks [24]

To analyze the differences in acceleration of the two objects, a necessary formula/relation to remember here is force = mass * acceleration. Given the different data in the problem, we can solve for the acceleration of each object. This is shown below:

Force = 15 N
M1 = 25 kg
M2 = 50 kg
a1 = ?
a2 = ?

For object 1:

15 N = 25 kg * a
a = 0.6

For object 2:

15 N = 50 * a
a = 0.3

Therefore, the acceleration of Object B is half that of Object A.

8 0

3 years ago