X=percentage of Cl-35
(1-x)=percentage of Cl-35
35(x)+37(1-x)=35.454
35x+37-37x=35.454
-2x=35.454-37
-2x=-1.546
x=-1.546/(-2)
x=0.773
0.773=77.3/100=77.3%
(1-x)=1-0.773=0.227
0.227=22.7/100=22.7%
answer: the percentages are: 77.3% of Cl-35 and 22.7% of Cl-37.
Answer: 1 atom
Explanation:
The loss of the remaining valence electron results in an ion with a +2 charge. The proper way of noting the charges on these ions is to use the systematic name for each ion, nickel (I) for the +1 ion and nickel (II) for the +2 ion.
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