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3 years ago

1. How would the series of figures change in the presence of a catalyst?

Chemistry

2 answers:

statuscvo [17]3 years ago

8 0

No, it won't change the amount of reactants nor the products as a catalyst will only provide an alternative path where lower activation energy is needed for the process to take place.

hope this explains it

If it does, please give it a brainliest :)))

Luda [366]3 years ago

8 0

Answer:

The figures represent a time sequence for a chemical reaction.

1. The presence of a catalyst would add new molecules, catalyst molecules, to the figures. Catalysts are not consumed as the reaction takes place, so its molecules would remain the same in all figures.

On the other hand, a catalyst speeds up a chemical reaction, so the quantity of reactant and product molecules would also change, with greater amounts of products and lower of reactants.

2. Yes, it would. As stated before, the presence of a catalyst would increase the amounts of products and decrease the amounts of reactants.

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Anvisha [2.4K]

Correct Answer: option 1 i.e. C

Reason:
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Answer:

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3 years ago

Suppose a compound is involved in three different reactions denoted R1, R2, and R3. Tripling the concentration of this reactant

pickupchik [31]

Answer:

The order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

Explanation:

The rate of a chemical reaction is the number of moles of reactants consumed per unit time or the number of moles of products formed per unit. the rate of a chemical reaction is affected by the concentration of reactants

The relationship between the rate of a chemical reaction and the concentration of its reactants is given by the rate law or equation.

Generally, the rate equation is given as;

Rate = k[A]ᵃ[B]ᵇ..., where k = rate constant which is independent of concentration of the reactants, [A] = concentration of reactant A, a = order of reaction A, [B] = concentration of reaction B, b = order of reaction B.

For the given reactions R1, R2 and R3

For R1; rate = 3, Concentration = 3[A]

3 = k[A]3ˣ

3¹ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 1

For R2; rate = 9, Concentration = 3[A]

9 = k[A]3ˣ

3² = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 2

For R1; rate = 1, Concentration = 3[A]

1 = k[A]3ˣ

3⁰ = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 0

Therefore, the order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

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3 years ago

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tino4ka555 [31]

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Explanation:

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For the formation of this bond type, each of the atom requires a odd or unpaired electrons.
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3 years ago

A person tries to heat up her bath water by adding 5.0 l of water at 80c to 60 l of water at 30c. what is the final temperature

Sophie [7]

We can calculate the final temperature from this formula :

when Tf = (V1* T1) +(V2* T2) / (V1+ V2)

when V1 is the first volume of water = 5 L

and V2 is the second volume of water = 60 L

and T1 is the first temperature of water in Kelvin = 80 °C +273 = 353 K

and T2 is the second temperature of water in Kelvin = 30°C + 273= 303 K

and Tf is the final temperature of water in Kelvin

so, by substitution:

Tf = (5 L * 353 K ) + ( 60 L * 303 K) / ( 5 L + 60 L)

= 1765 + 18180 / 65 L

= 306 K
= 306 -273 = 33° C

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3 years ago