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damaskus [11]
2 years ago
13

Which are examples of biotic factors? Select three options.

Chemistry
1 answer:
alina1380 [7]2 years ago
6 0

The biotic factors are bacteria soil, dead leaves, and stream water.

<h3>What is an abiotic factor?</h3>

An abiotic factor is a non-living part of an ecosystem that shapes its environment.

Biotic and abiotic factors make up a community via interaction.

Biotic factors are considered living things (having "life") while abiotic factors are simply non-living things.

The dead leaves of plants are an abiotic factor, the bacteria in soil are living matter and stream flowing, etc.

Hence, the biotic factors are bacteria soil, dead leaves, and stream water.

Learn more about the abiotic factor here:

brainly.com/question/12689972

#SPJ1

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Periods on the periodic table are
Roman55 [17]

Answer:

Periods on the periodic table of elements

Explanation:

In the periodic table of elements, there are seven horizontal rows of elements called periods. The vertical columns of elements are called groups, or families. (See also The Periodic Table: Metals, Nonmetals, and Metalloids.) In each period (horizontal row), the atomic numbers increase from left to right.

6 0
4 years ago
Explain and give examples of theories and laws (big bang molecular clock etc.)
bija089 [108]
1. Schrodinger's Cat- A many world's theory that describes quantum coherence and phenomenon. 
2. Newton's 1st Law- says that objects in rest will stay in rest and objects in motion will stay in motion. The most important lesson here is that an object in rest may not be in rest position.
3. Ohms law- says the current passing through an area is directly proportional to the voltage
5 0
3 years ago
I have a 5 liter container of oxygen (O 2 ) gas at 2.0 atm and 25 0 C, what mass of gas is inside this
Thepotemich [5.8K]

Answer:

m=13.1gO_2

Explanation:

Hello,

In this case, by using the ideal gas equation, we first compute the moles of oxygen at the given volume, pressure and temperature:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{2.0atm*5L}{0.082\frac{atm*L}{mol*K}(25+273.15)K}  =0.41mol

Then, since molar mass of gaseous oxygen is 32 g/mol, we compute the contained mass in grams as shown below:

m=0.41mol*\frac{32g}{1mol}\\\\m=13.1gO_2

Best regards.

3 0
4 years ago
This is due tomorrow... :How can you tell the mass was conserved in a chemical reaction?
kipiarov [429]

Answer:

Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions.

Explanation:

hope this help :)

3 0
3 years ago
Electrochemistry - Equilibrium
Ipatiy [6.2K]

Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

E⁰cell = (RT / nF ) lnK  , F is faraday constant T is 273 + 25 = 298 K

E⁰cell  =  1.46 - 1.21 = .25 V

n = 2

Putting the values

.25 = (8.314 x 298  lnK) / (2 x 96485 )

lnK = 19.47

K = 2.85 x 10⁸

2 )

Change in free energy Δ G

Δ G ⁰ = nE⁰ F

n = 4

E⁰ = .4 + .83 = 1.23 V

Δ G ⁰= 4 x 1.23 x 96485

= 474706 J / mol

3 )

E⁰cell = (RT / nF ) lnK

n = 2

1.78 = 8.314 x 298  lnK / 2 x 96485

lnK = 138.638

K = 1.62 x 10⁶⁰

8 0
3 years ago
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