Answer:
ab = 2
Step-by-step explanation:
Given equations
ax² +ax + 2 = 0
x² + x + b = 0
root of both the equation
x= 1
then we can plug in x = 1 in both the equation
ax² +ax + 2 = 0 x² + x + b = 0
a*1² +a*1 + 2 = 0 1² + 1 + b = 0
a +a + 2 = 0 1 + 1 + b = 0
2a + 2 = 0 2 + b = 0
2a = - 2 b = -2
a = -2/2 = -1
Thus,
a = -1
b = -2
a*b = -1*-2 = 2
ab = 2
Answer:
Not very sure, I think it would be $150, sorry if wrong
Step-by-step explanation:
The correct answer is letter A
Answer:
D
Step-by-step explanation:
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Answer:
(x+1)(x-3i) (x+3i)
Step-by-step explanation:
x^3 + x^2 + 9x+9
We will use factor by grouping
Factor out x^2 from the first group and 9 from the second group
x^3 + x^2 + 9x+9
x^2( x+1) + 9(x+1)
Factor out (x+1)
(x+1) ((x^2+9)
Now factor x^2+9
x^2 -(3i)^2 = (x-3i) (x+3i)
Replacing this
(x+1)(x-3i) (x+3i)
