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3 years ago

Simplify the algebraic expression:(x^5)^-2

Mathematics

1 answer:

maksim [4K]3 years ago

5 0

Answer:

1/x^10 should be the answer

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400g of rapberries and 300g of strawberries cost £7.46. 500g of strawberries cost £4.10 work out the cost of 300g of raspberries

MAXImum [283]

Answer: £5.39

Step-by-step explanation:

500g strawberries = 4.10

100 g = 0.82

300g = 2.46

400g raspberries = 7.46 - 2.46 = 5.00

100g = 1.25

300g = 3.75

200g strawberries = 0.82 * 2 = 1.64

3.75 + 1.64 = 5.39

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3 years ago

There are 8 2/3 pounds of walnuts in a container which will be divided equally into containers that hold 1 1/5 pounds this would

igomit [66]

you want 8 2/3 divided by 1 1/5 =

26/3 / 6/5

= 26/3 * 5/6 = 130 / 18

7 and 4/18 containers

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3 years ago

Andreus made 625$ mowing yards. He worked for 5 days and earned the same amount of money each day.How much money did he earn per

Alexandra [31]

Just divide 625$ by 5. The answer is 125$ per day.

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3 years ago

Read 2 more answers

Layla went shopping for camping equipment. After looking at several different stores, she bought a tent for $163.63 and a sleepi

Ghella [55]

Answer:

$297.09

Step-by-step explanation:

To answer this question, just add:

163.63 + 133.46 = 297.09

So, Layla spent $297.09 in all

Hope this helps :)

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3 years ago

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago

Simplify the algebraic expression:(x^5)^-2​

Simplify the algebraic expression:(x^5)^-2