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bearhunter [10]
3 years ago
13

Simplify the algebraic expression:(x^5)^-2​

Mathematics
1 answer:
maksim [4K]3 years ago
5 0

Answer:

1/x^10 should be the answer

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In ARST, r = 530 cm, s = 530 cm and t=950 cm. Find the measure of T to the
bearhunter [10]

Answer:

127.3

Step-by-step explanation:

​

T≈127.333≈127.3

∘

6 0
3 years ago
Please I’m really bad at these
grigory [225]
I think it’s the third or second
4 0
4 years ago
Qᴜɪᴢ-<br><br> What is <img src="https://tex.z-dn.net/?f=y%20~%2B~3y%20%3D%200%20~%2B~24" id="TexFormula1" title="y ~+~3y = 0 ~+~
zhuklara [117]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • What is \tt\:y+3y=0+24? Explain it.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\tt \: y + 3 y = 0 + 24

Combine y and 3y to get 4y.

\tt \: 4y=0+24

Add 0 and 24 to get 24.

\tt \: 4y=24

Divide both sides by 4.

\tt \: y=\frac{24}{4}  \\

Divide 24 by 4 to get 6.

\boxed { \boxed {\bf \: y=6 }}

8 0
3 years ago
The point-slope form of the equation of the line that passes through (-4,-3) and (12,1) is y-1=1/4(x-12). What is the standard f
ollegr [7]

Multiply by 4 and rearrange.

... 4y -4 = x - 12

... -4 = x - 4y - 12 . . . . . . subtract 4y

... x - 4y = 8 . . . . . . . . . . add 12. This is standard form.

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME!!!
IgorC [24]

Answer:

Option A)   Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(-5,-8),M(-1,-3)

substitute the values

r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}

r=\sqrt{(5)^{2}+(4)^{2}}

r=\sqrt{41}\ units

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}

d=\sqrt{(2)^{2}+(-6)^{2}}

d=\sqrt{40}\ units

so

\sqrt{40}\ units< \sqrt{41}\ units

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

4 0
4 years ago
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