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3 years ago

0.45 ÷ 225 (5th grade) basic math

Mathematics

2 answers:

Anna35 [415]3 years ago

5 0

The answer would be 0.002

Firlakuza [10]3 years ago

3 0

The answer to 0.45 / 225 = 0.002

Hope this helps you..

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-4y+20=-x solve for y

melisa1 [442]

Answer:

y = x/4 + 5

Step-by-step explanation:

Solve for y:

20 - 4 y = -x

Hint: | Isolate terms with y to the left-hand side.

Subtract 20 from both sides:

-4 y = -x - 20

Hint: | Solve for y.

Divide both sides by -4:

Answer: y = x/4 + 5

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3 years ago

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The points in the table lie on a line. find the slope of the line.

MatroZZZ [7]

Answer:

-7/6

Step-by-step explanation:

The slope formula can be used with any pair of points.

m = (y2 -y1)/(x2 -x1)

m = (1 -8)/(-2 -(-8)) = -7/6

The slope of the line is -7/6.

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3 years ago

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weeeeeb [17]

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3 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .