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2 years ago

If p is inversely proportional to the square of a, and p is 10 when q is 8, determine p when a is equal to 2

Mathematics

1 answer:

RoseWind [281]2 years ago

3 0

Your just gonna have to figure that out mY guy

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What is the period for tangent functions? (Answer in radians)

prisoha [69]

Answer: 2 radians

Step-by-step explanation: You welcome

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1 year ago

Ann bought 6 CDs that were each the same price. Including sales tax, she paid a total of 93.60. Of that total, 4.20was tax. What

Mariulka [41]

If you do 93.60-4.20=89.40. Then you do 89.40 divided by 6= 14.90 so each cd before tax would be $14.90.

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2 years ago

Factor x^4+xy^3+x^3+y^3 completely showing work.

babymother [125]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$x^4+xy^3+x^3+y^3\\\\=x^3*x+x*y^3+x^3+y^3\\\\=x(x^3+y^3)+x^3+y^3\\\\\boxed{=(x+1)(x^3+y^3)}\\$

Thank you

4 0

2 years ago

Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

3 years ago

Read 2 more answers

What is the quotient of 6 and -1/2

Grace [21]

Quotient means divide, meaning we'll divide 6 by -1/2.
$6 \div - \frac{1}{2}$
When dealing with fraction division, we flip the fraction in the second place and then change the problem to multiplication.
$6 \cdot - \frac{2}{1}$
Anything over 1 is just itself, so -2/1 becomes -2.
$6 \cdot -2$
Finally, we multiply 6 and -2.
$6 \cdot -2 = -12$
So the quotient of 6 and -1/2 is -12.

8 0

2 years ago

Read 2 more answers