3 years ago

Need today please

Physics

1 answer:

podryga [215]3 years ago

5 0

Answer:

yeah righto the correct answer mate would be D) :)

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An object has an acceleration of 18.0 m/s/s. If the net force was doubled and the mass were tripled then the new acceleration wo

kenny6666 [7]

Answer:

12.0 m/s²

Explanation:

Newton's second law:

F = ma

Solving for acceleration:

a = F/m

If force is doubled and mass is tripled:

a' = (2F)/(3m)

a' = ⅔ (F/m)

a' = ⅔ (18.0 m/s²)

a' = 12.0 m/s²

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3 years ago

What is the oxidation state of beryllium

Paha777 [63]

<span> Beryllium has an exclusive </span>+2<span> oxidation state in all of its compounds</span>

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3 years ago

A bond between a positively-charged particle and a negatively-charged particle is a(n) _______ bond.

weeeeeb [17]

The answer is an ionic bond.

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3 years ago

In the steady state 1.2 ✕ 1018 electrons per second enter bulb 1. There are 6.3 ✕ 1028 mobile electrons per cubic meter in tungs

bekas [8.4K]

Answer:

E=12.2V/m

Explanation:

To solve this problem we must address the concepts of drift velocity. A drift velocity is the average velocity attained by charged particles, such as electrons, in a material due to an electric field.

The equation is given by,

$V=\frac{I}{nAq}$

Where,

V= Drift Velocity

I= Flow of current

n= number of electrons

q = charge of electron

A = cross-section area.

For this problem we know that there is a rate of 1.8*10^{18} electrons per second, that is

$\frac{I}{q} = 1.2*10^{18}$

$A= 1.3*10^{-8}m^2$

$n=6.3*10^{28} e/m^3$

$\omicron{O} = 1.2*10^{-4}(m/s)(N/c)$ Mobility

We can find the drift velocity replacing,

$V = \frac{1.2*10^{18}}{(1.3*10^{-8})(6.3*10^{28})}$

$V= 1.465*10^-3m/s$

The electric field is given by,

$E= \frac{V}{\omicron{O}}$

$E=\frac{1.465*10^-3}{1.2*10^{-4}}$

$E=12.2V/m$

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3 years ago

A monkey has a bit of a heavy for on the gas pedal. As soon as the light turns green the monkey pushes the gas pedal to the floo

Andrei [34K]

Answer:

$s=6.86m/s^2$

Explanation:

Hello,

In this case, considering that the acceleration is computed as follows:

$a=\frac{v_{final}-v_{initial}}{t}$

Whereas the final velocity is 28.82 m/s, the initial one is 0 m/s and the time is 4.2 s. Thus, the acceleration turns out:

$a=\frac{28.82m/s-0m/s}{4.2s}\\ \\s=6.86m/s^2$

Regards.

3 0

3 years ago