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vlada-n [284]
3 years ago
8

A horizontal applied force of magnitude 25 N acts on a block sliding on a horizontal surface. The force of friction between the

block and the surface has magnitude 8 N. If the direction of the applied force is reversed which of the following is true?
A. the magnitude of the velocity of the block will remain constant.
B. the magnitude of the acceleration of the block decreases
C. The magnitude of the net force on the block increases as compared to before.
D. the magnitude of the net force on the block will remain the same as before​
Physics
1 answer:
kompoz [17]3 years ago
3 0

' A ' and ' D ' are both correct statements.

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A wire is made from a material having a temperature coefficient of resistivity of 0.0003125 (°C^-1). In an experiment, we mainta
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Answer:

The power decreases by 36%

Explanation:

Given:

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on substituting the values, we get

300 = 150²/R₀

or

R₀ = 75 Ω

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R = R₀[1 + α(T - T₀)]

where, α is the temperature coefficient of resistivity = 0.0003125 (°C⁻¹)

now, at

T₀ = 20° C

R₀ = 75 Ω

for

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we have

R = R₀[1 + α(T - T₀)]

substituting the values

we get

R = 75×[1 + 0.0003125 × (1820 - 20)]

or

R = 117.18 Ω

Now using the formula for power

We have,

P = V²/R

or

P = 150²/117.18 = 192 W

Therefore, the percentage change will be

= \frac{P-P_0}{P_0}\times 100

on substituting the values , we get

= \frac{192-300}{300}\times 100

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here, negative sign depicts the decrease in power

3 0
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This depends on the direction of the velocity vector to the magnetic field vector. The force is F=q(VxB)  ("x" is the cross product.)  The max force is when V and B are perpendicular.  Then F=qVB = (1.602e-19)(2000)(300) = 9.612e-14 N
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Find the electric energy density between the plates of a 225-μF parallel-plate capacitor. The potential difference between the p
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Answer:

Energy density will be 14.73 J/m^3

Explanation:

We have given capacitance C=225\mu F=225\times 10^{-6}F

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We know that there is relation between electric field and potential

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