Question

The CM of an empty 1300-kg car is 2.45 m behind the front of the car.

Answer 1

The center of mass of the car with all people seated will be 3.20 m far from the front of the car.

Taking the front of the car as reference:

m₁x₁ + m₂x₂ + m₃x₃ = mx

where,

m₁ = mass of empty car = 1300 kg

x₁ = distance of center of mass of empty car from front = 2.45 m

m₂ = mass of 2 people sitting in front = 2 x 60 kg = 120 kg

x₂ = distance of center of mass of 2 people sitting in front from the front    = 2.7 m

m₃ = mass of 3 people sitting in back seat = 3 x 60 kg = 180 kg

x₃ = distance of center of mass of 3 people sitting in the back seat from the front = 3.65 m

m = total mass of car with all people = 1300 kg + 120 kg + 180 kg = 1600kg

x = distance of center of mass of the car from the front when all are seated

Therefore,

(1300 kg)(2.45 m) + (120 kg)(2.7 m) + (180kg)(3.65 m) = (1300 kg)x

x = 4166 kg.m/1300 kg

x = 3.20 m

Therefore, the center of mass of the car with all people seated will be 3.20 m far from the front of the car.

Learn more about center of mass here:

brainly.com/question/17088562

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