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3 years ago

SOMEONE PLEASE HELP MATH

Mathematics

2 answers:

klio [65]3 years ago

5 0

Circumference = 2πr
3π=2πr
r=3π÷2π
r=3/2
area of a circle= πr²
=π×(3/2)²
=2.25π

topjm [15]3 years ago

5 0

Circumference = 2πr = 3π
r = 3π/2π
r = 3/2

Area = πr² = 9/4 π = 2.25π

In short, Your Answer would be Option B

Hope this helps!

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it takes Joey 1/16 of an hour to write one Thank you card how many cards can he write in 3/4 of an hour?

bearhunter [10]

To solve this problem you will need to use the cross product method:

1/16 of an hour → write 1 card

3/4 of an hour → write X cards

(3/4) ÷ (1/16) = X

0.75 ÷ 0.0625 = X

12 = X

Joey can write 12 Thank you cards in 3/4 of an hour.

There you go! I really hope this helped, if there's anything just let me know! :)

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3 years ago

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Find the distance between the two points in simplest radical form for (-6,1) and (-8,-4)

Elina [12.6K]

Answer:

Step-by-step explanation:

Δy =-4-1 = -5

Δx =-8-(-6) = -2

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3 0

3 years ago

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Find the area of this figure. Brainliest to first correct answer. Tysm

larisa [96]

Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2

Area of semicircle:
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Answer is C.
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3 years ago

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How do I do these...

a_sh-v [17]

Answer:

photomath bro

8 0

3 years ago

PLEASE HELP

irina [24]

Answer:

$12\sqrt{3}$ feet

Step-by-step explanation:

In a 30-60-90 triangle, the ratios of the side lengths of the triangle is $1:\sqrt{3} :2$

Where 1 is the shortest leg, root(3) is the longer leg, and 2 is the hypotenuse.

First we can set x equals to the length of the original pole, and so the shorter leg has a length of x/3 and using the ratio of side lengths, we can find that:

$\frac{x}{3} * \sqrt{3} = \frac{\sqrt{3} x}{3} = 12$

Solving for x, we find that

$x=\frac{36}{\sqrt{3} } = \frac{36 * \sqrt{3} }{\sqrt{3} * \sqrt{3} } = \frac{36 \sqrt{3} }{3} = 12\sqrt{3}$

So the length of the original pole would be $12\sqrt{3}$ feet

If you found this answer helpful, please consider marking it as brainliest, or give it a thanks and a 5 star review. Thanks!

6 0

2 years ago