<span>1) </span><span>Deduce
the two masses and see the amount of water was driven off when heated: </span><span>
<span>5.03 g -
4.23 g = 0.8 g H2O given off </span>
<span>2) Change
mass from grams to moles of H2O: </span>
<span>0.8 g H2O
/ 18 g H2O in 1 mole = 0.044 mol H2O </span>
<span>3) Change
left over mass to moles of BaCl2 .</span></span>
<span>
<span>4.23 g
BaCl2 / 207 g BaCl2 in 1 mol = 0.021 mol BaCl2 </span>
<span>4)Find
the ratio of mol H2O to mol BaCl2: </span>
<span>0.044 mol
H2O : 0.021 mol BaCl2 </span>
<span>5) The
resulting ratio is 2:1 so two H2O for each BaCl2, thus, the hydrate was named: </span>
<span>Barium
chloride di-hydrate</span></span>
Molarity= (number of moles of that substance) / (Volume of solution in litres)
7= (number of moles of HCl) / 0.05
Thus,
Number of moles of HCl = 7 x 0.05 = 0.35
The number of moles of HCl will remain unchanged.
Now, for new solution,
0.35= 0.35 / (New volume of solution in litres)
Thus,
New volume = 1 litre
Thus, amount of water added = 1- 0.05 litre = 5.0 M
Answer:
190 g
Explanation:
Knowing that:
- O₂ gas in air: 0.28 g O₂ / L of air
- Air inhaled at rest: 19.3 fl.oz. air / breath
- Human takes 20 breaths / min
The grams of oxygen gas (O₂) that a human at rest inhales in 1 hour (60 minutes) will be calculated as:
grams of O₂ = breaths in 1 hour * air inhaled per breath * amount of O₂ in air

grams of O₂ = 191.78 g
190 g of O₂ are inhaled in 1 hour (written in correct number of significant figures)
*In the calculation the amount of air inhaled per breath was converted from fl.oz. to Liters knowing that <em>1 L = 33.814 fl.oz.</em>
Answer:
OH−(aq), and H+(aq)
Explanation:
Redox reactions may occur in acidic or basic environments. Usually, if a reaction occurs in an acidic environment, hydrogen ions are shown as being part of the reaction system. For instance, in the reduction of the permanganate ion;
MnO4^-(aq) + 8H^+(aq) +5e-------> Mn^2+(aq) + 4H2O(l)
The appearance of hydrogen ion in the reaction equation implies that the process takes place under acidic reaction conditions.
For reactions that take place under basic conditions, the hydroxide ion is part of the reaction equation.
Hence hydrogen ion and hydroxide ion are included in redox reaction half equations depending on the conditions of the reaction whether acidic or basic.
Answer:
The answer to your question is: 0.25 l
Explanation:
Data
P1 = 1 atm
V1 = 0.5 l
P2 =2 atm
V2 = ?
T = constant
Formula
V1P1 = V2P2
Clear V2 from the formula
V2 = V1P1/P2
Substitution
V2 = (0.5)(1)/2 substitution
= 0.25 l result