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ahrayia [7]
4 years ago
10

Which statement describes an eletron

Chemistry
1 answer:
Vitek1552 [10]4 years ago
4 0
An electron carries a negative power to the atom. in each atom, the amount of protons and electrons are usually evened out so the atom is stable. the electrons of an atom are also found on the outside ring of an atom, unlike protons and neutrons, which are inside the atom. glad to help! :)
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On heating 5.03 g of hydrated barium chloride (BaCl2 XH2O), 4.23 g is left behind. What is the name of this hydrate? (
RSB [31]

<span>1)    </span><span>Deduce the two masses and see the amount of water was driven off when heated: </span><span>

<span>5.03 g - 4.23 g = 0.8 g H2O given off </span>

<span>2) Change mass from grams to moles of H2O: </span>

<span>0.8 g H2O / 18 g H2O in 1 mole = 0.044 mol H2O </span>

<span>3) Change left over mass to moles  of BaCl2 .</span></span>

<span>
<span>4.23 g BaCl2 / 207 g BaCl2 in 1 mol = 0.021 mol BaCl2 </span>

<span>4)Find the ratio of mol H2O to mol BaCl2: </span>

<span>0.044 mol H2O : 0.021 mol BaCl2 </span>

<span>5) The resulting  ratio is  2:1 so two H2O for each BaCl2, thus,  the hydrate was named: </span>
<span>Barium chloride di-hydrate</span></span>

8 0
4 years ago
If 1.8 L of water is added to 2.5 L of a 7.0 M KOH solution, what is the molarity of the new solution?
e-lub [12.9K]
Molarity= (number of moles of that substance) / (Volume of solution in litres)

7= (number of moles of HCl) / 0.05

Thus,

Number of moles of HCl = 7 x 0.05 = 0.35

The number of moles of HCl will remain unchanged.

Now, for new solution,

0.35= 0.35 / (New volume of solution in litres)

Thus,

New volume = 1 litre

Thus, amount of water added = 1- 0.05 litre = 5.0 M

6 0
3 years ago
Air is comprised predominantly of nitrogen (N2) and oxygen gas. The ambient air in this room contains about 0.28g of oxygen (O2)
viktelen [127]

Answer:

190 g

Explanation:

Knowing that:

  • O₂ gas in air: 0.28 g O₂ / L of air
  • Air inhaled at rest: 19.3 fl.oz. air / breath
  • Human takes 20 breaths / min

The grams of oxygen gas (O₂) that a human at rest inhales in 1 hour (60 minutes) will be calculated as:

grams of O₂ = breaths in 1 hour * air inhaled per breath * amount of O₂ in air

grams O_{2} = 60 min* 20 \frac{breath}{min} * 19.3 \frac{fl.oz. air}{breath} * \frac{1 L}{33.814 fl.oz.} * 0.28 \frac{g O_{2} }{L}

grams of O₂ = 191.78 g

190 g of O₂ are inhaled in 1 hour (written in correct number of significant figures)

*In the calculation the amount of air inhaled per breath was converted from fl.oz. to Liters knowing that <em>1 L = 33.814 fl.oz.</em>

7 0
3 years ago
In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidat
Vaselesa [24]

Answer:

OH−(aq), and H+(aq)

Explanation:

Redox reactions may occur in acidic or basic environments. Usually, if a reaction occurs in an acidic environment, hydrogen ions are shown as being part of the reaction system. For instance, in the reduction of the permanganate ion;

MnO4^-(aq) + 8H^+(aq) +5e-------> Mn^2+(aq) + 4H2O(l)

The appearance of hydrogen ion in the reaction equation implies that the process takes place under acidic reaction conditions.

For reactions that take place under basic conditions, the hydroxide ion is part of the reaction equation.

Hence hydrogen ion and hydroxide ion are included in redox reaction half equations depending on the conditions of the reaction whether acidic or basic.

4 0
3 years ago
Use Boyle’s law to complete the following:
mixas84 [53]

Answer:

The answer to your question is: 0.25 l

Explanation:

Data

P1 = 1 atm

V1 = 0.5 l

P2 =2 atm

V2 = ?

T = constant

Formula

          V1P1 = V2P2

Clear V2 from the formula

            V2 = V1P1/P2

Substitution

            V2 = (0.5)(1)/2  substitution

                  = 0.25 l       result

3 0
4 years ago
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