The force that keeps the puck moving is 0.25 N while the velocity of the puck is 3.7 m/s.
<h3>What is the centripetal force?</h3>
We know that the centripetal force is the force that acts on a body that is moving along a circular path. In this case, we are told that the puck is moving along a circular path hence it is acted upon by the centripetal force that acts on it.
The centripetal force in this case would be supplied by the weight of the object that is moving in the circular path. Thus we can write in our equation that;
Centripetal force = Weight of object = mg
m = mass of the object
g = acceleration due to gravity
Then;
W = 0.026 Kg * 9.8 m/s^2
W = 0.25 N
To obtain the velocity of the object;
FT = mv^2/r
v = √ FT r/m
v = √0.25 * 1.4/0.026
v = 3.7 m/s
Learn more about centripetal force:brainly.com/question/11324711
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Average speed (v) = total distance(d) / total time (t)
d = 57 + 87km = 144km
t = 2 + 3hrs = 5hrs
v = d÷t = 144÷5 = 28.8km/hr
Answer:
<h2>3.39 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula
m is the mass
v is the velocity
From the question we have
We have the final answer as
<h3>3.39 J</h3>
Hope this helps you
Answer:
Explanation:
If air resistance is ignored and assume UP and Toward Jason are the positive directions.
horizontal analysis
d = (vx₀)t
t = d/vx₀
horizontal analysis
0 = vy₀t + ½gt²
0 = vy₀(d/vx₀)+ ½g(d/vx₀)²
as vy₀ = v₀sin45 and vx₀ = v₀cos45 and are equal.
0 = d + ½g(d²/v₀²cos²45)
-d = ½g(d²/v₀²cos²45)
-dv₀² = ½g(d²/cos²45)
v₀² = -½g(d/cos²45)
v₀² = -½(-9.81(32.0/cos²45)
v₀² = 313.92
v₀ = 17.717787...
v₀ = 17.7 m/s
