Your desktop houses its system unit in a frame made of metal. what is the term for this frame?
1 answer:
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A) initial volume
We can calculate the initial volume of the gas by using the ideal gas law:
where
is the initial pressure of the gas
is the initial volume of the gas
is the number of moles
is the gas constant
is the initial temperature of the gas
By re-arranging this equation, we can find:
2) Now the gas cools down to a temperature of
while the pressure is kept constant:
, so we can use again the ideal gas law to find the new volume of the gas
3) In a process at constant pressure, the work done by the gas is equal to the product between the pressure and the difference of volume:
by using the data we found at point 1) and 2), we find
where the negative sign means the work is done by the surrounding on the gas.
We can calculate the initial volume of the gas by using the ideal gas law:
where
By re-arranging this equation, we can find
2) Now the gas cools down to a temperature of
while the pressure is kept constant:
3) In a process at constant pressure, the work done by the gas is equal to the product between the pressure and the difference of volume:
by using the data we found at point 1) and 2), we find
where the negative sign means the work is done by the surrounding on the gas.
Answer:
current in loops is 52.73 μA
Explanation:
given data
side of square a = b = 2.40 cm = 0.024 m
resistance R = 1.20×10^−2 Ω
edge of the loop c = 1.20 cm = 0.012 m
rate of current = 120 A/s
to find out
current in the loop
solution
we know current formula that is
current = voltage / resistance .................a
so current = 1/R × d∅/dt
and we know here that
flux ∅ = ( μ×I×b / 2π ) × ln (a+c/c) ...............b
so
d∅/dt = ( μ×b / 2π ) × ln (a+c/c) × dI/dt ...........c
so from equation a we get here current
current = ( μ×b / 2πR ) × ln (a+c/c) × dI/dt
current = ( 4π××0.024 / 2π(1.20×
) × ln (0.024 + 0.012/0.012) × 120
solve it and we get current that is
current = 4 ×× 1.09861 × 120
current = 52.73 × A
so here current in loops is 52.73 μA