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3 years ago

Pleqse help me do this thank you

Mathematics

1 answer:

SpyIntel [72]3 years ago

5 0

Answer:

84 grams; 5 ounces

Step-by-step explanation:

1oz = 28g

3*1oz = 3*28g

3 oz = 84g

140g = 5*28g = 5*1oz

140g = 5oz

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Your friend Michelle just graduated and has two job offers that she is considering. Both job offers pay the same, but JobA

just olya [345]

Money offered to Michelle per annum in Job A = $1700

Number of years she will work in job A = 5

Percentage of earnings per annum for her retirement plan = 6.60%

Money she will earn will be the simple interest at the end of 5 years.

We know that :

$\color{plum}{ \tt{Simple \: interest = \frac{Principle \ \: \times \: Rate \: \: \times \: \: Time}{100} }}$

Principal = $1700

Rate = 6.60%

Time = 5 years

Which means :

$= \frac{1700 \times 6.60 \times 5}{100}$

$= \frac{56100}{100}$

$= \color{plum}\$561$

We also know that :

$\color{plum}\tt \: Amount = Principal + Interest$

Amount Michelle will earn at the end of 5 years for her retirement plan :

$= 1700 + 561$

$=\color{plum}\bold{\$ 2261}$

2261 can be rounded off to 2260.

Therefore, Michelle will earn $2260 at the end of 5 years for her retirement plan.

5 0

3 years ago

What is the greatest common factor of 12 and 16

Assoli18 [71]

Answer:

Step-by-step explanation:

12 can be dived into 4 a total of 3 times. 16 can be divided into 4 a total of 4 times

5 0

3 years ago

Anyone? will mark you as brainlist

scoray [572]

Answer:

true

Step-by-step explanation:

5 0

3 years ago

A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears

marta [7]

Answer:

(a) The probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b) n = 28.09

Step-by-step explanation:

The random variable Yₙ is defined as the total numbers of dollars paid in n years.

It is provided that Yₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of Yₙ are:

$\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}$

(a)

For n = 20 the mean and standard deviation of Y₂₀ are:

$\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\$

Compute the probability that Y₂₀ exceeds 1000 as follows:

$P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z> 4.47)\\=1-P(Z$

**Use a z table for probability.

Thus, the probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b)

It is provided that P (Yₙ > 1000) > 0.99.

$P(Y_{n}>1000)=0.99\\1-P(Y_{n}$

The value of z for which P (Z < z) = 0.01 is 2.33.

Compute the value of n as follows:

$z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n} \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0$

The last equation is a quadratic equation.

The roots of a quadratic equation are:

$n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of n = 28.09.

8 0

3 years ago

Please help with both if you can! Thank you!

Alexxandr [17]

Answer:

15). is done

16).

$slope = \frac{ {y}^{1} - {y}^{o} }{ {x}^{1} - {x}^{o} } \\ = \frac{2 - ( - 2)}{ - 3 - 9} \\ = \frac{4}{ - 12} \\ slope = - \frac{1}{3}$

8 0

3 years ago

Pleqse help me do this thank you​

Pleqse help me do this thank you