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artcher [175]
3 years ago
15

Your friend Michelle just graduated and has two job offers that she is considering. Both job offers pay the same, but JobA

Mathematics
1 answer:
just olya [345]3 years ago
5 0

Money offered to Michelle per annum in Job A = $1700

Number of years she will work in job A = 5

Percentage of earnings per annum for her retirement plan = 6.60%

Money she will earn will be the simple interest at the end of 5 years.

We know that :

\color{plum}{ \tt{Simple \:  interest  =  \frac{Principle  \ \: \times  \: Rate  \:  \: \times \:  \:  Time}{100} }}

Principal = $1700

Rate = 6.60%

Time = 5 years

Which means :

=  \frac{1700 \times 6.60 \times 5}{100}

=  \frac{56100}{100}

= \color{plum}\$561

We also know that :

\color{plum}\tt \: Amount = Principal + Interest

Amount Michelle will earn at the end of 5 years for her retirement plan :

= 1700 + 561

=\color{plum}\bold{\$ 2261}

2261 can be rounded off to 2260.

Therefore, Michelle will earn <u>$2260</u> at the end of 5 years for her retirement plan.

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Line GJ is tangent to point A at point G.<br><br> If AG = 9 and GJ = 12, find AJ.
svlad2 [7]
Okay we know that tangent-chords creat 90 degree angles so what we have is a right triangle with a base of 9 and a height of 12, so do Pythoagoreas Theorem and we have 81+144=225 square root of 225 is 15 and that is AJ
8 0
3 years ago
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What is the area of the figure?<br><br> A.234 in.^2<br> B.315 in.^2<br> C.225 in.^2<br> D.252 in.^2
saul85 [17]

Let's imagine we enclosed the entire shape in a 15 inch wide, 21 inch tall rectangle, area 315 sq inches.

From that rectangle we have to take away the 3x6 bottom left corner, and a strip 21-6=15 inches long and 3 inches wide on the right.

A = 15×21 - 3×6 - 3×15 = 315 - 63 = 252 sq in

Answer: D.   252 inches squared, last choice

5 0
3 years ago
Hey um... I have a question about Cumulative frequency diagram. Its in the picture. Please help I will give you reward I promise
Mice21 [21]

Answer: see below

Step-by-step explanation:

(i)

200/2 = 100

Find 100 on cumulative frequency and the correspinding time: 14 minutes. So the answer is 14 minutes.

(ii)

First, find the lower quartile —> 200/4 = 50

Upper quartile —> 200/(3/4) = 150

Find the difference: 150 - 50 = 100

So the interquartile range is 100

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5 0
3 years ago
( _ + i ) + ( 4 _ ) = 10 - 7i
Margaret [11]
2 8 if not I’m so sorry pls forgive me
4 0
3 years ago
Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

6 0
3 years ago
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