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denis23 [38]
3 years ago
7

Dos cargas Q1=2pc y Q2=4pc estan separadas por una distancia de 6cm ¿con que fuerza se atraen?

Physics
1 answer:
noname [10]3 years ago
3 0

Here we can use coulomb's law to find the force between two charges

As per coulombs law

]tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we have

k = 9 * 10^9

q_1 = 2pC

q_2 = 4pC

r = 6cm = 0.06 m

now by using the above equation we have

F = \frac{9*10^9 * 2*10^{-12} * 4*10^{-12}}{0.06^2}

F = 2 * 10^{-11} N

so here the force between two charges is of above magnitude and this will be repulsive force between them as both charges are of same sign.

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A wave can be described as?
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Answer:

<em>B) The disturbance of particles in an area.</em>

Explanation:

<em>A wave involves transmission of  energy from one place to another by the actual disturbance of the particles of the medium.</em>

<em />

6 0
2 years ago
Three observers watch a train pull away from a station toward the right of the platform. Observer A is in one of the train’s car
juin [17]

Observer A is moving inside the train

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So here observer B will see the actual motion of train which is moving in forward direction away from the platform

Observer C is inside other train which is moving in opposite direction on parallel track. So as per observer C the train is coming nearer to him at faster speed then the actual speed because they are moving in opposite direction

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Now as per Newton's II law

F = ma

Now if train apply the brakes the net force on it will be opposite to its motion

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5 0
3 years ago
From the lens equation calculate the position of the following images produced by a convex lens.
fiasKO [112]

Explanation:

(i)

O is the object and I is the image.

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Refer above image. 1

(ii)

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Refer above image. 2

(iii)

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2 years ago
A ball is thrown up in the air. When it falls back down and reaches the ground, it's final downward velocity is 8.0 m/s. What wa
hram777 [196]
Given : Time taken to reach the maximum height t=3 s a=−g=−10m/s
2


The initial velocity of the ball can be calculated by,
Using v=u+at
∴ 0=u−10×3 ⟹u=30 m/s

Using S=ut+
2
1
​
at
2

∴ S=30×3+
2
1
​
×(−10)×3
2
=45m
8 0
2 years ago
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