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Art [367]
2 years ago
15

Which one of the following types of electromagnetic wave travels through space the fastest?

Physics
1 answer:
Setler [38]2 years ago
4 0

Answer:

As a result, light travels fastest in empty space, and travels slowest in solids. In glass, for example, light travels about 197,000 km/s.

Explanation:

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The radio frequencies push one air molecule that then bumps into a different air molecule.....which then hits another and another causing a line of crashing molecules that lead inside your ear and hits your ear drum causing it to vibrate which causes the sounds.
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You are waiting to turn left into a small parking lot. a car approaching from the opposite direction has a turn signal on. you s
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4 years ago
Of the solar radiation entering the atmosphere, about ___% reaches the surface directly as direct radiation.
strojnjashka [21]
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8 0
3 years ago
The Earth's escape speed (the speed you need to get away forever) is about 40,000 kilometers per hour. Escape speed depends on t
Anvisha [2.4K]

The Moon s escape speed will be smaller than Earth's.

  • What is escape speed:

The minimum speed that is required for an object to free itself from the gravitational force exerted by a massive object.

The formula of escape speed is

  • v = \sqrt{\frac{2GM}{R} }

where

v is escape velocity

G is universal gravitational constant

M is mass of the body to be escaped from

r is distance from the center of the mass

we can say that,

Escape speed depends on the gravity of the object trying to hold the spacecraft from escaping.

we know that,

The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second.

since, v ∝ g

The Moon s escape speed will be smaller than Earth's.

Learn more about escape speed here:

<u>brainly.com/question/15318861</u>

#SPJ4

5 0
2 years ago
A cannon of mass 5.71 x 103 kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires a 7
zheka24 [161]

Answer:

541.14 m/s

Explanation:

We are given that

Mass of cannon=m_1=5.71\times 10^3 kg

Mass of shell,m_2=73.5 kg

Initial velocity of shell,v=547 m/s

We have to find the velocity of shell fired from this loose cannon.

According to law of conservation of momentum

m_1v_1+m_2v_2=m_1u_1+m_2u_2

Initial momentum of system=0

m_1v_1=-m_2v_2

v_1=-\frac{m_2v_2}{m_1}

When the cannon is bolted to the ground then only shell moves and kinetic energy of system equals to kinetic energy of shell

Kinetic energy of shell,K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 73.5(547)^2}=1.09\times 10^7 J

K.E of shell=\frac{1}{2}m_1v^2_1+\frac{1}{2}m_2v^2_2

K.E of shell=\frac{1}{2}m_1(-\frac{m_2v_2}{m_1})^2+\frac{1}{2}m_2v^2_2

K.E of shell=\frac{1}{2}(\frac{m^2_2v^2_2}{m_1}+\frac{1}{2}m_2v^2_2)

2K.E of shell=m_2v^2_2(\frac{m_2}{m_1}+1)

Velocity of shell fired from this loose cannon,v_2=\sqrt{\frac{2k.E}{m_2(\frac{m_2}{m_1}+1)}

v_2=\sqrt{\frac{2\times 1.09\times 10^7}{73.5(\frac{73.5}{5.71\times 10^3}+1)}

v_2=541.14m/s

Hence, the velocity of shell fired from this loose cannon would be 541.14 m/s

5 0
3 years ago
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