Answer:
A force of μk⋅60N is needed to keep a 60-newton rubber block moving across level, dry asphalt in a straight line at a constant speed.
Explanation:
Answer: See explanation
Explanation:
Gravity is simply referred to as the force of attraction between two particles or masses. Through gravity, the moon moves round the Earth.
Gravity also causes a fruit to fall from its tree. It can also cause an object to roll and fall from the table to the ground. In gravity, distance and mass are vital.
Answer:
D. accelerated
Explanation:
According to Newton's first law of motion, an object always remains in its state of rest or in uniform motion until an external unbalanced force is acted upon the object. This means if an external unbalanced force is acted on the object, it will come to a non-uniform motion i.e., an accelerated motion.
Let me first get you clear that uniform motion is determined by a constant velocity and a state of rest is considered by a zero velocity or speed. But, here we have an unbalanced force acting on the object. This means the object will change its velocity and hence, it has an accelerated motion.
<h2>
a) Initial velocity = 83 ft/s</h2><h2>
b) Object's maximum speed = 99.4 ft/s</h2><h2>
c) Object's maximum displacement = 153.64 ft</h2><h2>
d) Maximum displacement occur at t = 2.59 seconds.</h2><h2>e)
The displacement is zero when t = 5.70 seconds</h2><h2>
f) Object's maximum height = 153.64 ft</h2>
Explanation:
We have velocity
v(t)= -32t + 83
Integrating
s(t) = -16t²+83t+C
At t = 0 displacement is 46 feet
46 = -16 x 0²+83 x 0+C
C = 46 feet
So displacement is
s(t) = -16t²+83t+46
a) Initial velocity is
v(0)= -32 x 0 + 83 = 83 ft/s
Initial velocity = 83 ft/s
b) Maximum velocity is when the object reaches ground, that is s(t) = 0 ft
Substituting
0 = -16t²+83t+46
t = 5.70 seconds
Substituting in velocity equation
v(t)= -32 x 5.70 + 83 = -99.4 ft/s
Object's maximum speed = 99.4 ft/s
c) Maximum displacement is when the velocity is zero
That is
-32t + 83 = 0
t = 2.59 s
Substituting in displacement equation
s(2.59) = -16 x 2.59²+83 x 2.59+46 = 153.64 ft
Object's maximum displacement = 153.64 ft
d) Maximum displacement occur at t = 2.59 seconds.
e) Refer part b
The displacement is zero when t = 5.70 seconds
f) Same as option d
Object's maximum height = 153.64 ft
Answer:
The value of the maximum charge the cloud can hold Q = 177.08 coulomb
Explanation:
Given data
Electrical Field E = 4 × 
the maximum charge the cloud can hold is given by
Q = E A x ---- (1)
where A = area = 5 ×
x = electrical Permittivity of air = 8.854 × 
Q = (4 × ) (5 × ) ( 8.854 × )
Q = 177.08 coulomb
This is the value of the maximum charge the cloud can hold.
