In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 4.8 m/s at an
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Explanation:
It is given that,
The acceleration of a particle, (negative as the particle is decelerating)
Initial distance, x₁ = 20 m
Initial time, t₁ = 4 s
New distance x₂ = 4 m
Velocity, v = 10 m/s
(A) Calculating initial distance using second equation of motion as :
u = 21 m/s
When velocity of the particle is zero, time taken is t (say). Using first equation of motion as :
t = 2.62 seconds
So, the velocity of the particle is zero at t = 2.62 seconds.
(B) Velocity at t = 11 s
v = 13 m/s
Total distance covered at t = 11 s. The overall path travelled by the particle during its entire journey is called total distance covered.
d = 132.48 m
So, the distance travelled by the particle at t = 11 seconds is 132.48 meters.
Any point in the wire has 1.12 x . electrons flow per second.
- Electric current in a wire, where electrons serve as the charge carriers, is a measurement of the amount of charge that moves through any point of the wire in a given amount of time.
- A free electron is drawn to a proton to become neutral if an electron is added to the wire.
- Lack of electrons can result from pushing electrons out of their orbits.
- Electric current is the name given to the constantly moving electrons in wire.
The current is the quantity of charge Q flowing through a certain point of the wire in a time interval of .
I = .
by using this relationship
I=1.80 A, we can find the charge passing any point in the wire in 1 second:
Electric Charge, Q = 1.80 C.
To find how many electrons corresponds to this charge, we should divide this value by the charge of a single electron
charge of the electron = 1.6 x C.
No. of Electrons = Q/q = = 1.12 x
.
To learn more about Electric current refer,
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