7×20 and 7×2000 are similar. The amount of zeros are the dependent factor.
7×20= 140
7×2000= 14000
The base equation is 7×2=14
Any additions of zeroes in this formula will be added at the end result.
Ex.
7×2=14
7×20=140
7×200=1400
70×200=14000
700×200=140000
Answer:
Number of calls expected in next week by manager = 7940
Average Number of calls that call center agent will attend in an hour =7 calls
It is also given that, Call center remain open for 10 hours 5 days a week.
Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week ,Part time agents work 20 hours a week but are only on calls 17 hours per week .
⇒Number of hours worked by full time agents × Number of calls attended in an hour × Number of full time agents + Number of hours worked by Part time agents × Number of calls attended in an hour × Number of Part time agents ≤ 7940
⇒35 × 7×Number of full time agents +17 × 7 ×Number of Part time agents ≤ 7940
Option A
⇒35×15×7+17×7×15
= 3675+1785
= 5460
Option B
⇒35 ×7×20+17×7×7
=4900 +833
= 5733
Option C
⇒35×20×7 +17×20×7
=4900+2380
=7280
Option D
⇒25 × 35×7+17×7×5
=6125 +595
=6720
Option E
⇒28×35×7+17×7×10
=6860+1190
=8050
Option E, ⇒ 28 full time agents and 10 part time agents , is best to meet the scheduling needs is most appropriate, that is nearer to 7940 calls.
Answer: ∠ABE=20°
Step-by-step explanation:
∵ AB=BC
∴ ΔABC is a isosceles triangle
∵ ∠A=30
∴ ∠C=30
∵ The interior angle sum of triangle is 180°
∵ ∠A+∠B+∠C=180
30+∠B+30=180
∠B+60=180
∠B=120 (∠ABC)
∵ ∠EBD+∠ABE+∠ABC=linear pair
∴∠EBD+∠ABE+∠ABC=180°
4x+2x+120=180
6x+120=180
6x=60
x=10
∠ABE=2x=2(10)=20°
Hope this helps!! :)
Please let me know if you have any question
Answer:
I believe it is c> 34
Step-by-step explanation:
Correct me if i'm wrong
Answer:
11
Step-by-step explanation:
Given that in a sample of n=6, five individuals all have scores of X=10 and the sixth person has a score of x=16
i.e. the data entries are
10,10,10,10,10,16
Sum = 66
No of items n = 6
Average = sum/no of entries
=
Average is 11.
mean of this sample is 11
