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Shkiper50 [21]
3 years ago
10

Find dy/dx of y =

" class="latex-formula"> (x^2)
Mathematics
1 answer:
NikAS [45]3 years ago
7 0

Step-by-step explanation:

y = log_2 x^2  \\  \therefore  y =  \frac{log x^2}{log2}\\ (By\:change\:of\:base\:law) \\ \\ \therefore  y =  \frac{2log x}{log2}\\\\ differentiating \: both \: side \: w \: r \: t \: x. \\ \\ \frac{dy}{dx}  = \frac{2}{log2}   \bigg(\frac{d}{dx} log x \bigg) \\  \\  \therefore \frac{dy}{dx}  = \frac{2}{log2}    \bigg( \frac{1} {x} \times \frac{d}{dx}  x \bigg) \\ \\  \therefore \frac{dy}{dx}  = \frac{2}{log2}    \bigg(\frac{1}{x} \times  1\bigg) \\ \\  \huge \red{ \boxed{\therefore \frac{dy}{dx}  = \frac{2}{xlog2}}}

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