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tino4ka555 [31]
4 years ago
8

What is the gcf of 25a^2 - 100

Mathematics
2 answers:
vazorg [7]4 years ago
5 0
<span>25a^2 - 100
= 25(a^2 - 4)

GCF = 25

Hope it helps</span>
masha68 [24]4 years ago
3 0
U subtract all of it
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Which sum will be neither positive nor negative?<br> 07+(-6)<br> 0 3+2<br> 0-6 + 6<br> 0-4-(-4)
makkiz [27]

Step-by-step explanation:

The awnser is -6+6 because it would end up being 0, which is not positive nor negative

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3 years ago
Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
SVEN [57.7K]

The given function is

h(x)=-16x^2+300x+20

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.

Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

h=-\frac{b}{2a}

Where a = -16 and b = 300.

\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

\begin{gathered} k=-16(9.375)^2+300(9.375)+20 \\ k=-1406.25+2812.5+20=1426.25 \end{gathered}

Hence, the maximum height is 1426.25 feet.

At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

t=2\cdot9.375=18.75

Hence, the rocket hits the ground after 18.75 seconds.

6 0
1 year ago
Solve for x. Round your answer to the nearest tenth if necessary.
posledela

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Step-by-step explanation:

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2 years ago
A rectangular sandbox has an area of 55 square feet. find the length and width of the box if the length is one more than twice t
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The length is 5

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3 years ago
I need help with this problem
Anarel [89]

The midpoint lines are half the opposite side length.

Line DE is given as 7 , So Line F = 7 x 2 = 14

Line EF is given as 12, so Line D = 12 x 2 = 24

Line DF is given as 16, so line E = 16 x 2 = 32


The perimeter is the sum of the 3 sides:

Perimeter = 14 + 24 + 32 = 70

6 0
4 years ago
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