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Makovka662 [10]
3 years ago
5

Can you help me on all of the problems?

Mathematics
1 answer:
Lisa [10]3 years ago
8 0
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The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds. Using the empirical ru
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If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.

<h3>What is the z-score?</h3>

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

The z-score is given as

z = (x - μ) / σ

Where μ is the mean, σ is the standard deviation, and x is the sample.

The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.

Then the probability that a cat will weigh less than 11 pounds will be

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Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.

More about the z-score link is given below.

brainly.com/question/15016913

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