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algol13
3 years ago
5

Find the solutions of this system of equations 10x-5y=-20 7x-5y=-26

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer:

i think $25.00

Step-by-step explanation:


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Ending time is 10:08 am. Elapsed time 30 min
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10:38 am ...........
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3 years ago
Carla Compra borrowed $800 at 14% for one year. She paid a $15 processing fee.
Taya2010 [7]
800×0.14=112
112+15=127
(127÷800)*100==15.88%
4 0
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A population of 120,000 grows 3% per year for 15 years, how much will the population be after 15 years?
Wewaii [24]
270,000 is the answer because you have three over 100 so you do 100 divided by three which give you 0.15 then you do 120,000 times 0.15 to find out how much it grows per year to get 18,000 then you multiply 18’000 by 15 and get 270’000
3 0
3 years ago
Which two functions are inverses of each other?
liraira [26]

Answer:

Option 3 - f(x)= 4x, g(x) = \frac{1}{4}x

Step-by-step explanation:

To find : Which two functions are inverses of each other?

Solution :

Two functions are inverse if f(g(x))=x=g(f(x))

Now, we find one by one

1) f(x)= x, g(x) = -x

f(g(x))=f(-x)=-x\neq x

Not true.

2) f(x)= 2x, g(x) = -\frac{1}{2}x

f(g(x))=f(-\frac{1}{2}x)=2\times(-\frac{1}{2}x)=-x\neq x

Not true.

3) f(x)= 4x, g(x) = \frac{1}{4}x

f(g(x))=f(\frac{1}{4}x)=4\times(\frac{1}{4}x)=x

g(f(x))=f(4x)=\frac{1}{4}\times 4x=x

i.e. f(g(x))=x=g(f(x)) is true.

So, These two functions are inverse of each other.

4) f(x)= -8x, g(x) =8x

f(g(x))=f(8x)=8\times(-8x)=-64x\neq x

Not true.

Therefore, Option 3 is correct.

6 0
3 years ago
Find 10 partial sums of the series. (round your answers to five decimal places.) ∞ 15 (−4)n n = 1
nikklg [1K]
Given

\Sigma_{n=1}^\infty15(-4)^n

The first 10 partial sums are as follows:

S_1=\Sigma_{n=1}^{1}15(-4)^n=15(-4)=\bold{-60} \\  \\ S_2=\Sigma_{n=1}^{2}15(-4)^n=\Sigma_{n=1}^{1}15(-4)^n+15(-4)^2 \\ =-60+15(16)=-60+240=\bold{180} \\  \\ S_3=\Sigma_{n=1}^{3}15(-4)^n=\Sigma_{n=1}^{2}15(-4)^n+15(-4)^3 \\ =180+15(-64)=180-960=\bold{-780} \\  \\ S_4=\Sigma_{n=1}^{4}15(-4)^n=\Sigma_{n=1}^{3}15(-4)^n+15(-4)^4 \\ =-780+15(256)=-780+3,840=\bold{3,060} \\  \\ S_5=\Sigma_{n=1}^{5}15(-4)^n=\Sigma_{n=1}^{4}15(-4)^n+15(-4)^5 \\ =3,060+15(-1,024)=3,060-15,360=\bold{-12,300}

S_6=\Sigma_{n=1}^{6}15(-4)^n=\Sigma_{n=1}^{5}15(-4)^n+15(-4)^6 \\ =-12,300+15(4,096)=-12,300+61,440=\bold{49,140}

The rest of the partial sums can be obtained in similar way.
7 0
3 years ago
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