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Kazeer [188]
3 years ago
13

Miss Hudspeth has a supply of 30% alcohol solution and a supply of 50% alcohol solution. How much of each solution should she mi

x together to get 60mL of 34% alcohol solution for an experiment in her chemistry class
Mathematics
1 answer:
Vikki [24]3 years ago
6 0
Um id say 20% of the 30% solution and 14% of the 50 % i think, does it give you answer choices?
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alukav5142 [94]

Answer:

-4/3

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y2 - y1 / x2 - x1

-9 - (-1) / 0 - (-6)

-4/3

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Suppose f (x) = x^2. Find the graph of f(x+2)
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\bf ~~~~~~~~~~~~\textit{function transformations}&#10;\\\\\\&#10;% templates&#10;f(x)={{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;~~~~y={{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;f(x)={{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\\\&#10;f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\\\&#10;f(x)={{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\\\\&#10;--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;~~~~~~if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;~~~~~~if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;~~~~~~if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind,

\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}

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8 0
2 years ago
URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.
dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

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Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

\large{ {tan}^{2}  \theta =  {( -  \frac{3}{2}) }^{2}  - 1} \\   \large{ {tan}^{2}  \theta =   \frac{9}{4}  - 1} \\   \large{ {tan}^{2}  \theta = \frac{9}{4}   -  \frac{4}{4} \longrightarrow  \frac{5}{4}  } \\  \large{tan \theta =  \frac{ \sqrt{5} }{ \sqrt{4} } } \\  \large \boxed{tan \theta =  \frac{ \sqrt{5} }{2} }

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\large{ \cancel{ tan \theta  =  \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta =  -  \frac{ \sqrt{5} }{2} }}

Answer

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3 0
2 years ago
Select True or False for each statement.
Tpy6a [65]

Answer:

1. True

2. False

3. True

4. False

5. True

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1. For a real number a, a + 0 = a.

This is true, any number plus zero is that number.

2. For a real number a, a + (-a) = 1.

This is false.  Adding a negative number is the same as subtracting that number. So a + (-a) = a - a = 0

3. For a real numbers a and b la-bl = |b-al.

This is true.  Absolute value represents the distance between two numbers.  This number can never be negative, therefore la-bl = |b-al.

4. For real numbers a, b, and c, a +(bº c) = (a + b)(a + c).

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5. For rational numbers a and b when b# o, is always a rational number.

True, a rational number is one that can be written as a fraction with two integers.  The quotient of two rational numbers can always be written as a fraction with integers.

8 0
3 years ago
Read 2 more answers
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