The Z- score representing the 99th percentile is given by 2.33
Problems of commonly distributed samples can be solved using the z-score formula.
For a set with a standard deviation, the z-score scale X is provided by:
Z = ( x- mean )/ standard deviation
Z-score measures how many standard deviations are derived from the description. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the scale is less than X, that is, the X percentage. Subtract 1 with p-value, we get the chance that the average value is greater than X.
To Find the z-result corresponding to P99, 99 percent of the normal distribution curve.
This is the Z value where X has a p-value of 0.99. This is between 2.32 and 2.33, so the answer is Z = 2.33
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This could be wrong but the remaining pieces he can cut is 3 because if you divide 400 with 8 , it’s 35 as the answer, so then subtract 35 with 15 till you can subtract 15 from it
Yes because the results that are statistically significant are also practically significant
n+6=6nStep-by-step explanation:
200 x 0.99. Or you can do 200/100 which is 2. then multiply that by 99 which gets you 99 which is 198.
